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/vqc/ - Virtual Quantum Computer

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77656e No.12463 [Open thread][Last50 Posts]

The virtual quantum computer (VQC) is a grid made of constructably infinite elements that follow a known pattern. It is indexed using e, n, and t, where e is the column, n is the row, and t is the specific element in the cell.

The grid in its entirety serves as the superposition. The required input parameters to collapse the superposition are d and e, which are trivial to calculate for all c that is the difference of two squares. When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows a path to calculate the factors of c instead of searching for them. It can be understood using only the basic operations of arithmetic and sqrt. All currently-known patterns can be found within one thread here >>6506

C# VQC generator - pastebin.com/XFtcAcrz

Java VQC generator - pastebin.com/2MPYrJVe

Python VQC generator - pastebin.com/NZkjtnZL

Glossary

Look-up

A pattern used to calculate the factors of c, like a value look-up table.

Column

All cells for a given e

Row

All cells for a given n

Cell

All entries for a given e,n (not to be confused with an entry itself.)

Entry; record; element

A set of variables corresponding to a factorization for a given c. The legend to read entries is {e:n:d:x:a:b} (e, n, t) = c

Example: {1:5:12:7:5:29} (1, 5, 4) = 145

ab record; nontrivial factorization

The element that contains the factorization of c that is not 1*c, hencPost too long. Click here to view the full text.

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a308ea No.12844

Feels like the bookshelf in Interstellar. Something about Love (which is also Truth, who together with Truth is G-d) is the only thing that transcends both time & space (simultaneously).

Something about a trip, and a vision, and a crystal globe, and a rose bush named Love in the midst of a Fallen Pine.

All while a good friend stepped on a peace of glass.

Blessssss

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File: 88f631dfeb59c1c⋯.png (355.31 KB,1296x893,1296:893,Screen Shot 2018-06-24 04.png)

File: 4f7d237bc70d31e⋯.png (189.54 KB,500x375,4:3,Einstein Autism.png)

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bb404b No.6506 [Open thread][Last50 Posts]

VQC:

At this point, a good strategy would be to have a thread that is used to post patterns from The End grid.

Patterns that apply to all c in the grid.

Patterns that apply to all cells in a row.

Patterns that apply to all cells in a column.

Special rows.

Special columns.

It was hinted before and was useful to me, by enumerating all the patterns in one place, the answer will materialise.

You are looking for a key shortcut.

The grid does the ALL the work for you.

Suggestion…

Either here or a worker thread(s), discuss each rule or pattern.

When consensus is reached, put the rule or pattern in the key thread.

This process and result of this process may surprise you, more than you think.

It may change the way you think.

It may be advantage you can apply in other problem solving.

This is how you win.

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f4926f No.12503

>>12498

Ideas you're working on aren't established, fully-understood grid patterns. Why do you keep posting in here instead of the main thread?

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File: 2fdb2eab99edf2f⋯.jpeg (136.21 KB,1920x1080,16:9,the end.jpeg)

446221 No.6415 [Open thread]

Welcome to /vqc/. New people tend to have some trouble understanding what this board is about, so this thread serves as an explanation. The long and detailed version will follow in the replies to this post. Here’s a shortened version:

>early on during the beginning of Q in November of last year

>someone calling themselves VQC starts posting Q-style crumbs to the annoyance of most and the curiosity of others

>makes some interesting claims, such as Agartha being real

>starts posting code around the end of November, calling it a Virtual Quantum Computer (hence the name) with unlimited qubits

>says it can be used to prove that P=NP, to factorize semiprimes (which allows us to break RSA encryption), and overall to demonstrate new mathematic principles that have been hidden from the public by the elite

>suggests that making these mathematic principles public is an important part of the idea of the public having freedom, despite it meaning large changes to encryption being necessary

>the code uses two numbers, i and j, to calculate several variables

>i and j are implemented in a nested loop, which in simple terms means j starts at 0 and increases by 1 each time the variables are calculated until it is equal to i, at which point i, which also started at 0, increases by 1, and j starts at 0 again

>a = i-j, b = i+j, and the other variables are calculated from these

>in the context of factorizing semiprimes, the two variables a and b multiply together and give us c, and if a and b are prime numbers, c is a semiprime

>semiprimes are a key component of RSA encryption because of the fact that, with current factorization methods, it would take thousands of years to factorize 1024-bit semiprimes, making it seemingly unreasonable to crack

>the variables are put into a spreadsheet (which we call The End) with the variable e as the x axis and the variable n as the y axis

>several anons have been working together for the last 7 months to try to figure out how we can use the gridPost too long. Click here to view the full text.

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342e32 No.9046

There are a bunch of variables we can directly calculate and a bunch of variables we can't directly calculate. The idea is that we use the patterns we've learned and the variables and cells we can directly calculate and somehow end up with one of the variables we can't directly calculate. Nobody's figured out how to do that yet. Those patterns and cells are all in >>6506

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File: af8d1f77315c65f⋯.png (14.02 KB,2048x512,4:1,bdd2ccb26c213d4ab84de08fb0….png)

860584 No.193 [Open thread]

Board rules:

>no spam - this includes posting over and over that you think VQC is LARPing with no evidence, or trying to derail any of the general threads with irrelevant information

That's pretty much it. You're only going to get banned if you seem to be intentionally shitting up the place, and if that's the case we'll try asking you to stop first.

This thread is dedicated to the way the board is run. If you have any suggestions about how we should do things, or you think any other posters are causing trouble, feel free to discuss it here.

AA/ArchiveAnon is the board owner, and he can be privately contacted at thebuttonnexttocapslocktwice@protonmail.com. We would all prefer if you would ask about things on the board so that everything is public, though. If you think I'm doing a bad job of running the board, don't hesitate to mention why so I can stop doing whatever I'm doing. If you think I've become a tyrannical dictator and that I'm not listening to your criticisms, the nature of this website is such that you can start a new VQC-related board, and our community is small enough that you wouldn't have any trouble convincing everyone to join you if they agreed. This board is not about me; it's about the collaborative effort.

There is also a /vqc/ Discord server. Ask Topol either in RSA general or his EZ Bake general thread if you'd like to join. This Discord server is strictly for off-topic conversations and half-baked ideas that we don't think are worth posting here on the board. We are all dedicated to making this a public disclosure, so if you think some of us are plotting behind closed doors, you're welcome to join the server and post screenshots to the board.

The End

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05c381 No.7959

Just to clarify for future reference, I'm not any of the people known as Archive Anon (such as German Archive Anon) from /qresearch/. I guess it's a common name. Sage because nobody asked but someone might wonder at some point.

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49576b No.2134 [Open thread][Last50 Posts]

As requested by VQC:

"Is there anyone more practical with access to 3D printing as we can run the sonoluminescence thread in parallel and it will be quite rewarding to build a fully functioning cold fusion generator?

Perfectly safe, boils water.

Thought it may be fun for those who prefer to build stuff."

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2fd9ab No.12686

File: 18e36e79435cb81⋯.pdf (402.43 KB,Massey_paper_ZPE.pdf)

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a86b57 No.12687

https://m.youtube.com/watch?v=Jn89boAl3uc

Video by Tom Bearden talking about Sono. He really gets into it at about 40min mark

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a86b57 No.12688

>>12687

1hr and 14mins he mentions it is RF (RADIO FREQUENCY) pulses not sound like InTraditional Sono.

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a86b57 No.12693

https://m.youtube.com/watch?v=xKOtKTLudOU

Bob greenyer talking about this type of stuff.

Mater is simply an antipode of compressed energy.

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a86b57 No.12697

https://m.youtube.com/watch?v=UgoAC2p8bZg

Some mention of Sono in this one as well. I missed the timestamp

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1ad7bf No.11618 [Open thread][Last50 Posts]

The virtual quantum computer (VQC) is a grid made of constructably infinite elements that follow a known pattern. It is indexed using e, n, and t, where e is the column, n is the row, and t is the specific element in the cell.

The grid in its entirety serves as the superposition. The required input parameters to collapse the superposition are d and e, which are trivial to calculate for all c that is the difference of two squares. When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows a path to calculate the factors of c instead of searching for them. It can be understood using only the basic operations of arithmetic and sqrt. All currently-known patterns can be found within one thread here >>6506

C# VQC generator - pastebin.com/XFtcAcrz

Java VQC generator - pastebin.com/2MPYrJVe

Python VQC generator - pastebin.com/NZkjtnZL

Glossary

Look-up

A pattern used to calculate the factors of c, like a value look-up table.

Column

All cells for a given e

Row

All cells for a given n

Cell

All entries for a given e,n (not to be confused with an entry itself.)

Entry; record; element

A set of variables corresponding to a factorization for a given c. The legend to read entries is {e:n:d:x:a:b} (e, n, t) = c

Example: {1:5:12:7:5:29} (1, 5, 4) = 145

ab record; nontrivial factorization

The element that contains the factorization of c that is not 1*c, hence, nontriPost too long. Click here to view the full text.

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1c2175 No.12492

File: 73f67f4df2b3d20⋯.png (296.76 KB,1956x1038,326:173,Fermat_s_theorem.png)

Fermat's difference of squares is laid out here.

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7c523d No.12496

>>12477

>a square on both sides of the modulo equation, which is equivalent to a difference of squares.

This is a reference to Dixon's factorization method, discussed in RSA #17 posts >>10466, >>10468, >>10469

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a315ee No.12497

File: 793b73da1a223fa⋯.png (483.67 KB,2550x3300,17:22,c6107_n2_n1_exploration.png)

Hello anons.

Here's the idea clearly mapped out in sheet form.

"once you c i[t] you can't un c i[t]"

We can approximate c by starting at the (na transform) and using the offset for find test (a) and (b) values to find cTest.

Easier to see than explain with words.

the distance between aTest and bTest approximates n

precise n can be found via logical search from that point.

This is how we use the Offset to solve.

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a172b7 No.12499

File: eb87776b72f00a3⋯.png (128.21 KB,1348x396,337:99,Screen_Shot_2024_04_21_01.png)

Anyone paying attention to this board now has everything needed to solve the problem we set out to solve as a team on 11/30/2017.

As RSA #19 comes to a close, here are my thoughts as the last remaining active idea contributor.

The Offset has been clearly explored and laid out for all to see.

The fact that (-f,1) and (e,1) both contain valid factorizations for any given semiprime c makes a lookup solution possible, as Chris promised.

In row 1, we know that every a[t] value represents a * n or (an).

The two columns allow us to split any a[t] location value into (a) and (n)

We then use simple algebra to solve for (a) and (n).

The offset also exists for (bn).

Any a[t] is also b[t] when we apply the correct formula.

When we derive any (a) value , we can easily calculate b using c/a =b

Then we use algebra to get the x value for (b)

Since (n) is equal for (an) and (bn) we also have an additional check, with n1 being related to the a[t] and n2 being related to b[t]

The problem is solved in the realm of ideas.

Now let's write the code.

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92a96a No.12500

File: 51517c961b62655⋯.png (1.33 MB,1200x1062,200:177,Screenshot_2024_02_26_at_8….png)

File: 112d349ea7db444⋯.png (1.67 MB,1125x1123,1125:1123,Screenshot_2024_03_13_at_7….png)

File: 8eb32ad0aae0ad7⋯.jpeg (110.81 KB,954x870,159:145,purple_toxicity.jpeg)

File: f6704d9f390cff2⋯.jpeg (1.68 MB,1222x1622,611:811,World_Hierarchy_Pyramid.jpeg)

File: d9839e0435025ac⋯.png (287.81 KB,516x389,516:389,Screen_Shot_2023_01_02.png)

To finish out this RSA #19 bread, I found a very helpful simplification for the offset formulas.

Chris seemed to prefer d[t]-d, however I prefer this way since it's very simple and clear.

Here it is.

For a(n-1) and (an) the offset is as follows:

For (an) we know (xx +e) / 2 = (an) for any given i[t]

For a(n-1) the easiest way is to say ((x+1) ^ 2 - f) / 2 = a(n-1)

For (bn) we also know (xx + e) / 2 = (bn) for any given i[t]

For b(n-1) the easiest way is to say ((x-1) ^ 2 - f) / 2 = b(n-1)

Less chance of math mistakes, and easier to follow.

This also makes solving our overall problem easier.

If we have a given (a), we can now solve for (b) within the parameters of c = a * b using the offset.

I used some cool algebra software to help, long simplification process.

Here's the formula for b:

(2x + 2d) / 2 = b

If we know b, we can solve for x with the following:

(2b - 2d) / 2 = x

for example, c6107 b = 197

(394 - 156) / 2 = 119 = x

Now we also have a (b) value.

Because we can also calculate n1 and n2, every paring along the c = a * b pathway can be evaluated.

“The most useful information constrains values as c increases”

So the solution path is simply to pick an x value like x = (d-1)/2 and get the a value.

Then, we use c/a = b to find b

Then, we use the formula to get the x value for b

Then, we calculate a * b = cTest along with n1 and n2 Post too long. Click here to view the full text.

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File: ef1d309f0a928f9⋯.png (172.53 KB,434x674,217:337,RoyQuigley.png)

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15ab65 No.846 [Open thread][Last50 Posts]

A-Notations:

1. I speak in onions.

2. I have no idea what you need right now.

3. I'm just trying to figure out existence.

4. Feel free to put random notes and ideas here.

5. You don't know what I'm looking for, either.

6. Think of this as a thread to pluck while working on music.

7. There are no stupid questions, only faggots.

8. Imagine VQC as a Shamanic Journey Guide.

9. 369, 9 To 3, 12, 1+2=3, it works all the way up.

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2453b6 No.11418

>>10923

Who have you been?

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6f9377 No.11549

File: ec0e385a9fda076⋯.jpg (74.99 KB,755x1024,755:1024,1601560350470m.jpg)

>>11418

"Have been" indeed. Banned from Twatter 3x now. Not necessarily comfortable dropping my handle here. Got an email I could send it to?

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2453b6 No.11552

>>11549

I meant on the board lol

Can you point to some of your posts?

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64974c No.12213

File: 27933676a9be8c5⋯.png (155.14 KB,319x499,319:499,Screenshot_at_2021_12_18_2….png)

Topol… indeed.

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1a121b No.12298

bump?

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File: d4fa9a6a3693f4c⋯.jpg (117.88 KB,600x600,1:1,99 - 0E7aLKk.jpg)

37bf0f No.4379 [Open thread][Last50 Posts]

==Want to learn how to program?== =#MeToo.=

Alright, let's talk about it faggots. I don't know shit about programming, but I love to learn. Luckily, we have excellent program anons who can help. Just ran my first snippet of code today, "Hello World". All anons welcome, this is a forum for asking questions and getting answers. Also, ProgramAnons can pose skill appropriate challenges for us newbs if they think we're ready or if they just want to mess with us. Goal is to help everyanon advance in their coding or teaching skillz.

-VA

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02b8b3 No.11530

Hey Anons! Anyone willing to advise on how to compile c# code?

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8f6c73 No.11569

>>8760

>I'm willing to try Jupiter, just finally have a grasp of compiling and running AA's programs from my terminal, and was able to generate the CSV Grid in Visual Studio. I'm reluctant to jump ship to a new platform, unless it really is much better.

The Jupyter platform isn't so important, more of using Julia as the language.

If you're happy with java (and AA is an expert), then go with that. If you want to dabble in Julia, let me know.

Jupyter notebooks are just a tool / environment for the language. Can also run Python within them as well.

Similarly, you can use the REPL (regular command interface), and do this via other Dev tools as well (Atom, Sublime Text, etc.).

The Binary manipulations are all handled as well, either in the base language, or with packages.

This bred is young, and not getting a lot of use (kek), so if you want to work here, we could do that.

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e54a56 No.11586

>>11569

Thanks MM!

I appreciate you.

I'll have time to work over the weekend!

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8f6c73 No.11809

YouTube embed. Click thumbnail to play.

>>11586

>>11586

THIS. Fuck C. We're here to break C.

Links are in the vidya description:

https://julialang.org/downloads/

https://computationalthinking.mit.edu/Fall20/installation/

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8f6c73 No.12211

In a cell, add the following to trigger these packages to be loaded:


begin
	using Random
	using Serialization
	using Formatting
	using PlutoUI
	using Primes
	using Match
	using Markdown
end

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File: a10907b56fa9ade⋯.jpg (160.75 KB,660x405,44:27,photo-5-1502123063010.jpg)

2254ad No.9094 [Open thread]

The truth is right under our feet.

____________________________
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6c5989 No.11744

YouTube embed. Click thumbnail to play.

>>9094

Hollow Earth Chronicles with Justin Faull

Nov 25, 2017

''Right beneath our feet…"

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File: 8eaf338ab376a88⋯.png (136 KB,1308x1017,436:339,binary_pattern_from_last_t….png)

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38a251 No.10952 [Open thread][Last50 Posts]

The virtual quantum computer (VQC) is a grid made of constructably infinite elements that follow a known pattern. It is indexed using e, n, and t, where e is the column, n is the row, and t is the specific element in the cell.

The grid in its entirety serves as the superposition. The required input parameters to collapse the superposition are d and e, which are trivial to calculate for all c that is the difference of two squares. When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows a path to calculate the factors of c instead of searching for them. It can be understood using only the basic operations of arithmetic and sqrt. All currently-known patterns can be found within one thread here >>6506

C# VQC generator - pastebin.com/XFtcAcrz

Java VQC generator - pastebin.com/2MPYrJVe

Python VQC generator - pastebin.com/NZkjtnZL

Glossary

Look-up

A pattern used to calculate the factors of c, like a value look-up table.

Column

All cells for a given e

Row

All cells for a given n

Cell

All entries for a given e,n (not to be confused with an entry itself.)

Entry; record; element

A set of variables corresponding to a factorization for a given c. The legend to read entries is {e:n:d:x:a:b} (e, n, t) = c

Example: {1:5:12:7:5:29} (1, 5, 4) = 145

ab record; nontrivial factorization

The element that contains the factorization of Post too long. Click here to view the full text.

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6d41f3 No.11725

File: e823ee05394a33c⋯.png (68.93 KB,1200x555,80:37,259_7x37_geom3.png)

>>11722

>We are not allowed to know if have free will. Hence it is given to us by God and only taken by the hand of man.

I read this as taken from our own selves, due to inaction (based on fear, procrastination, etc.). Thanks for that, just need to execute.

Like the truth comment!

It appears image posting is working again, would you please try again from earlier? (attachment here to validate).

Also, have some questions regarding the 'f' patterns (if you're going to be awake for a bit).

>>11724

>There's a shortcut to the demand curve called remote viewing the stock market

Sending love, and hope you're killing it AA.

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720521 No.11726

Another example.

A new person goes on a talk show clAiming they have the ultimate key to lasting longer in the marrital bed, no more thinking about dying parents or pets. Intrigued the host asks what it is. You get out a picture.

Meghan Markle.

Before the shock wears off, you immediately ask what rhymes with MeAgain Markle?

Kipper Trench.

You then 100% commit to Meghan Markle rhyming with Kipper Trench.

This is squaring "thinking past the sale". You plant the negative thought. You then associate it with something negative and cause an argument over whether it is true.

Second order.

Result: everyone who watched MeAgain Markle be called the free anti climax service now, through random arguments about rhymes, associates her fanny with nasty niffs and all hated things about fish.

Its always about rates of change, however abstract.

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67c985 No.11727

>>11725

I have questions too but they're less math-related so I'll try not to interrupt, although for whatever reason he seems keep missing my posts.

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67c985 No.11728

Might as well fill the thread

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67c985 No.11729

>>11728

bloop

( >>11618 )

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File: 47dbb8d95855ec8⋯.png (1.99 MB,5228x4205,5228:4205,1 1.png)

File: e16247e93be1bbe⋯.png (55.21 KB,1456x1023,1456:1023,1 2.png)

File: ebe4ae01ead5515⋯.gif (1.61 MB,1024x1024,1:1,1 3.gif)

fd3a9d No.10193 [Open thread][Last50 Posts]

The virtual quantum computer (VQC) is a grid made of constructably infinite elements that follow a known pattern. It is indexed using e, n, and t, where e is the column, n is the row, and t is the specific element in the cell.

The grid in its entirety serves as the superposition. The required input parameters to collapse the superposition are d and e, which are trivial to calculate for all c that is the difference of two squares. When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows a path to calculate the factors of c instead of searching for them. This pattern can be understood using only the basic operations of arithmetic and sqrt.

Glossary

Look-up

A pattern used to calculate the factors of c, like a value look-up table.

Column

All cells for a given e

Row

All cells for a given n

Cell

All entries for a given e,n (not to be confused with an entry itself.)

Entry; record; element

A set of variables corresponding to a factorization for a given c. The legend to read entries is {e:n:d:x:a:b} (e, n, t) = c

Example: {1:5:12:7:5:29} (1, 5, 4) = 145

ab record; nontrivial factorization

The element that contains the factorization of c that is not 1*c, hence, nontrivial.

1c record; trivial factorization

The element generated from setting a=1 and b=c

Mirror element

The element in -f corresponding to an element in e, in the context of a given c.

SievePost too long. Click here to view the full text.

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dd5c5b No.10957

File: f52c4f8749aa027⋯.png (138.17 KB,1289x1018,1289:1018,rsa100_binary_thing.png)

>>10956

Here are the binary a[t]s for the same branching, just as an idea.

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effedd No.10958

I've been thinking about the "lookup x", if anyone remembers that. At the time nobody seemed to have any idea what it meant to have an x value in (e,1) or (f,1) that would lead to the solution that wouldn't just be the x we were already looking for (thereby rendering it meaningless to apply it to (e,1) and (f,1) since we'd already have an unknown that would give us the solution). It's a lookup x that's meant to either give us na or n-1. I'm thinking maybe this refers to the binary chunk thing. It's the only thing that's come up since he introduced the concept of a lookup x that seems to give it any meaning (a lookup x that gives us the element where na or n-1 is a chunk at the end of a[t] in binary). I've run some tests looking for na or n-1 in binary at the end of a[t] in elements other than the six we were using before and I haven't run into any that it doesn't work for yet, but the ones it works for where it isn't one of the six known elements, I haven't seen anything yet that would give a path to this x value. Here are two examples (I had to use numbers in the thousands or these tests would have taken hours (RSA_100 would have taken at most ten octovigintillion years with this algorithm, so maybe not that one) - also there are other examples that found n-1 but these both happen to be na):

(123,222,521) = {123:222:3482:1041:2441:4967}, f=-6842, c=12124447, u=631, i=3704, j=1263

The x values for the six known elements are (e,1) 12120965, 3481, 12127929 and (f,1) 12107038, 3480, 12114003

Found na at (f,1) x=11659973 === (146580344905683,1,5823023) = {146580344905683:1:141105366169899:11646045:141105354523854:141105377815946}, f=-135630387434116, c=19910724361941423765278575884, u=5823022, i=141105366169900, j=11646046

12107038 - 11659973 = 447065, so the solution element is 223533 elements below the (f,1) a[t]=c*(BigN-1) element

(3012,276,472) = {3012:276:2555:942:1613:4049}, f=-2099, c=6531037, u=608, i=2831, j=1218

The x values for the six known elements are (e,1) 6528482, 2554, 6533592 and (f,1) 6528481, 2555, 6533592

Found na at (e,1) x=6292398 === (3012,1,3146200) = {3012:1:19797142589106:6292398:19797136296708:19797148881506}, f=-39594285175201, c=39192685469339Post too long. Click here to view the full text.

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c1582f No.10959

>>10958

AA. Great post.

> It's a lookup x that's meant to either give us na or n-1.

>I've run some tests looking for na or n-1 in binary at the end of a[t] in elements other than the six we were using before and I haven't run into any that it doesn't work for yet

Was it the binary patterns that revealed the (n-1) and (na) values? Your post is vague about how you arrived at your results.

>It makes a lot of sense assuming this binary thing is what he was talking about in February and March though.

I have questions about how the sorting occurs for a binary search. Please post all your results for each test, and I'll take the time to analyze them in binary to look for matching chunks. M's breakdown needs to be analyzed in binary too.

>>10949

This was also a great post, working on the clues given. Thanks M. Let's analyze in binary to see if anything pops up.

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effedd No.10960

Filling the thread

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effedd No.10961

Filling the thread more

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File: 4bb677d0ab8b8aa⋯.jpeg (71.78 KB,851x644,37:28,fermat.jpeg)

ce4680 No.5774 [Open thread][Last50 Posts]

>The other thread will describe how to take the work done to solve Fermat Last theorem relates to our approach and why two objects that are identical types in number theory had to be proved so in a difficult to under proof, when in reality, with the right number system or model, this should have been obvious or a tautology.

Fermat's Last Theorem: there are no three positive integers a, b and c that satisfy the equation a^n + b^n = c^n for any n>=3.

You can read about the work done to solve Fermat's Last Theorem here:https://en.wikipedia.org/wiki/Wiles%27s_proof_of_Fermat%27s_Last_Theorem

It involves the modularity theorem and elliptic curves, both of which VQC has already mentioned.

>The next piece that uses the same approach is not going to go into the details of elliptic curves and modular forms, it will be more about why these two identical things looked different, because realising they were the same thing solved a 350 year old math problem called Fermat's Last Theorem.

>What does it tell us about a language like maths when you need a virtually incomprehensible proof JUST to show two things are identical?

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d2546b No.8149

File: 423949304a9977b⋯.png (539.52 KB,550x563,550:563,the-best-funny-pictures-of….png)

File: 3a253a326384b8b⋯.jpg (130.18 KB,400x400,1:1,Sailor-Moon-Logic-Meme-sai….jpg)

File: fba41091e34e1cd⋯.jpg (31.54 KB,450x406,225:203,logic-no-logic-450x406.jpg)

File: 9d69a9e96df23c7⋯.jpg (398.4 KB,1548x1024,387:256,no-1s-logic-message-to-fan….jpg)

>>5979

https://www.philosophybasics.com/branch_logic.html

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d2546b No.8474

YouTube embed. Click thumbnail to play.

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00a056 No.10016

File: 01769b943a26458⋯.png (59.15 KB,635x539,635:539,RiemannFractal.png)

>>5774

https://arxiv.org/PS_cache/chao-dyn/pdf/9406/9406003v1.pdf

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00a056 No.10019

>>10016

Don't ask.

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a7ba5c No.10258

YouTube embed. Click thumbnail to play.

"Why was this visual proof missed for 400 years? (Fermat's two square theorem)"

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File: 6e0119fd029fc68⋯.png (136.9 KB,1000x540,50:27,Abbreviations.com.png)

File: 47dbb8d95855ec8⋯.png (1.99 MB,5228x4205,5228:4205,VQC-map9.png)

File: e16247e93be1bbe⋯.png (55.21 KB,1456x1023,1456:1023,even-odd-both.png)

File: ebe4ae01ead5515⋯.gif (1.61 MB,1024x1024,1:1,e-x.gif)

File: 5338d2d9885a60e⋯.jpg (606.19 KB,1151x1870,1151:1870,Ekita玄.jpg)

fd3baa No.9114 [Open thread][Last50 Posts]

Virtual Quantum Computer

The virtual quantum computer (VQC) is a grid made of constructably infinite elements that follow a known pattern.

The grid in its entirety serves as the superposition. The input parameters that collapse the superposition are d and e, which are trivial to calculate for all c that is the difference of two squares. When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows a path to calculatethe factors of c instead of searching for them.

The grid is indexed using e, n, and t, where e is the column, n is the row, and t is the specific element in the cell.

Glossary

Look-up

A pattern used to calculate the factors of c, like a value look-up table.

Column

All cells for a given e

Row

All cells for a given n

Entry; record; element

A set of variables corresponding to a factorization for a given c. The legend to read entries is {e:n:d:x:a:b} (e, n, t) = c

Example: {1:5:12:7:5:29} (1, 5, 4) = 145

ab record; nontrivial factorization; prime element

The element that contains the factorization of c that is not 1*c, hence, nontrivial.

1c record; trivial factorization

The element generated from setting a=1 and b=c

Mirror element

The element in -f corresponding to an element in e, in the context of a given c.

Cell

All entries for a given e,n (not to be confPost too long. Click here to view the full text.

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91695b No.10188

YouTube embed. Click thumbnail to play.

>>10186

https://www.youtube.com/watch?v=2xT6fcm4V1o

We should all take the time to watch this. I picked it up from the alien bread in qresearch. It is somewhat related to here… … "suspend disblief" is stated over and over through this video. Enjoy.

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226172 No.10189

File: 5e7ce57bbb02fe1⋯.jpg (58.19 KB,800x426,400:213,9y88.jpg)

>>10188

It's a good one.

I listened to a while ago.

Memewhile, this is what the Yang Gang is up to.

I feel like our time is spent better here.

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735c18 No.10190

>>10188 WRWY. Great clip - Long in .realtime., listening now..

How would this have _sounded_ in the days of CAMELOT? Would it have _resonated_?

What a timeline (…CONTINUUM…) WE're on!!

>>>/qresearch/7483952

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226172 No.10191

File: 13f3b777c01f2ee⋯.png (1.04 MB,775x775,1:1,IcelandicWWG1WGA-v3.png)

File: 6fa5696172537b8⋯.png (687.27 KB,949x633,949:633,SlovenianWWG1WGA.png)

File: 3700a2e7c819d76⋯.png (644.67 KB,765x470,153:94,OzzieWWG1WGA .png)

File: 81719fbcfb72a61⋯.png (695.46 KB,980x613,980:613,RussianWWG1WGA.png)

FILLER INJECTION

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226172 No.10192

File: f2b8b42c55b20ba⋯.png (268.35 KB,500x500,1:1,GnatShift.png)

File: e03a24642aa4740⋯.png (194.53 KB,729x493,729:493,methlife-new-logo.png)

File: 93de37f012684fe⋯.png (2 MB,1328x1959,1328:1959,Hunter-does-dallas.png)

File: 45e49d2b097a800⋯.png (697.58 KB,883x497,883:497,Davies504stein.png)

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File: 8f63d73dd2af813⋯.jpg (1.13 MB,1116x1611,124:179,rawImage.jpg)

File: 60f78db28a564dd⋯.pdf (155.03 KB,Distance-between-arithmeti….pdf)

File: f66c522ae2edd17⋯.pdf (158.82 KB,A-Simple-and-Improved-Algo….pdf)

File: 3e6be4b683194a5⋯.pdf (142.11 KB,Integer-factorization-is-i….pdf)

File: 39c879ea0b3478e⋯.pdf (86.62 KB,Using-Simulated-Annealing-….pdf)

233bf8 No.9994 [Open thread]

Thread for PDF archiving and consolidation

6 posts and 25 image replies omitted. Click [Open thread] to view. ____________________________
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233bf8 No.10002

File: 5209d91eb8b66e1⋯.jpg (176.76 KB,1024x931,1024:931,5209d91eb8b66e12167748bd7b….jpg)

>>10001

Worse than "Pee is stored in the balls?"

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8063dd No.10003

>>10002

Hey at least mine was contextual

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233bf8 No.10066

File: ac350f1e5a43e25⋯.pdf (1.16 MB,FastHacks—RSA-Factorizatio….pdf)

File: eb85ba72230e51f⋯.pdf (218.56 KB,Faster-deterministic-integ….pdf)

File: 1a315b2bb48d112⋯.pdf (106.22 KB,The-Completion-of-Euler's-….pdf)

File: 666a9216354d42a⋯.pdf (336.29 KB,Turning-Euler's-Factoring-….pdf)

File: 6eb93c9db50d9f1⋯.jpg (113.51 KB,788x861,788:861,Bjws7emCEAEpSyi.jpg)

Daniel J. Bernstein, Nadia Heninger and Tanja Lange — FastHacks: RSA Factorization in the Real World

David Harvey and Edgar Costa — Faster Deterministic Integer Factorisation

Richard Blecksmith, John Brillhart and Michael Decaro — The Completion of Euler's Factoring Formula

James McKee — Turning Euler's Factoring Method into a Factoring Algorithm

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233bf8 No.10069

File: 6b24341e3406d16⋯.pdf (116.7 KB,On-the-Number-of-Prime-Num….pdf)

File: e991a0997713a71⋯.pdf (104.46 KB,Equivalences-to-the-Rieman….pdf)

File: 8af3bcf9ac82ed5⋯.jpg (1.19 MB,2920x3145,584:629,45.jpg)

File: 59c8c3be384ab4a⋯.pdf (128.45 KB,Integration-As-Summation.pdf)

File: 6edb56c0b678805⋯.pdf (195.7 KB,Integration-as-the-Reverse….pdf)

Bernhard Riemann tr. by David R. Wilkins — On the Number of Prime Numbers Less Than a Given Quantity

J. Brian Conrey and David W. Farmer — Equivalences to the Riemann Hypothesis

Engineering Maths First Aid Kit — Integration as Summation

Math Centre — Integration as the Reverse of Differentiation

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233bf8 No.10070

File: acf3e877125c429⋯.jpg (2.08 MB,5236x3490,2618:1745,0c114c61307e4b88a71f60eb8f….jpg)

File: fcf5661bf5ead76⋯.pdf (300.16 KB,Generalized-Alcuin's-Seque….pdf)

File: 62a416258caf8c9⋯.pdf (300.25 KB,Introduction-to-Groups-Rin….pdf)

File: a5518d382c6427c⋯.pdf (358.85 KB,Shor’s-Discrete-Logarithm-….pdf)

File: 95a76c0978676f8⋯.pdf (1.18 MB,Elliptic-Modular-Forms-and….pdf)

Daniel Panario, Murat Sahin and Qiang Wang — Generalized Alcuin’s Sequence

H. A. Priestly — Introduction to Groups, Rings and Fields

John Proos and Christof Zalka — Shor’s Discrete Logarithm Quantum Algorithm for Elliptic Curves

Don Zagier — Elliptic Modular Forms and Their Applications

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File: 027e05eedeb4772⋯.jpg (102.22 KB,1280x720,16:9,Smartania.jpg)

23ed9b No.7839 [Open thread]

Remember all those times you took the difference of some value or the remainder of some value from c and a solution value surfaced, but it didn't work for other example c values?

Well, inspired by those lists of values I developed that happen to make x and x+n show up somewhere, I don't think those paths are useless coincedences and should be forgotten, I think we should make a list of them.

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23ed9b No.8098

File: 138a0efe39595aa⋯.png (15.42 KB,184x715,184:715,Screenshot from 2018-11-06….png)

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23ed9b No.8156

when gcd(d,e) != 1 it is equal to a

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23ed9b No.8158

"there is an entire family of numbers that can be factored in 1 step"

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23ed9b No.8159

>>8158

which is when x appears in the tree

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0c14f9 No.9444

The elements that d is between in row one relatively reliably give the correct i value for c (nontrivial). Previously, it took 4 element calculations to check these, but with parity matching, it can be found in 2 calculations.

With the addition of the elements that c is between in i[t], the solution i is also given by j[t] relatively reliably, and it works on examples that fail the original SeeIt calculation.

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