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/vqc/ - Virtual Quantum Computer

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File: 06df73c8f0672da⋯.pdf (47.5 KB,vqc simple up to qc.pdf)

ddab04 No.42 [Open thread]

I'm the person who has been working on making a really simple explanation of everything. I've been attempting to cover everything anyone who wildly stumbles upon this might not know (so for example how RSA works, what big O notation means, what a nested loop is, as well as obviously explaining the grid and the whole point of all of this). Here's most of what I've done so far. I haven't had a lot of free time so I thought the most useful use of my time would be working on that "map" that VQC suggested we make. Obviously anyone is welcome to either suggest that this is complete shit or make changes or point out anything incorrect or work on their own version or anything like that. This work isn't about the individuals. It's about the result we get by working together. That's why if we can all get on the same level in terms of understanding, things might get done more quickly.

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ddab04 No.732

>>730

Have you thought of starting from near the bottom of where you currently are and pasting the pieces together in a different Paint-style program when you're done?

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09b357 No.735

>>732

That's a pretty good idea.

I think I will do that.

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20b5b1 No.6139

File: 4ddffff94165375⋯.png (893.33 KB,1251x711,139:79,Capture.PNG)

>>42

Hey, really appreciate the work you've done to help new people get up to speed. I've been following Q since about post #6, but I was lurking and never followed to /cbts (figured it was a board for fanboys). I kind of regret that now.

Anyway, your .pdf "What is The Grid" has been an excellent help thus far. It makes getting the program together pretty trivial; I'm sure the fun has just begun.

I'm no expert in Quantum computing–I was considering making it a focus, but from what I understood it was probably going to be another twenty years before the technology went mainstream, which would put me pretty close to retirement age (maybe I was wrong). I do know that most of the explanations out there seem to be overcomplicating things and making them mysterious, which is annoying. I think people tend to emphasize the weird truths just because they're fascinating, but don't necessarily represent the whole picture. For instance, pic related is a video I'd some time ago, which is interesting but does nothing to explain why the phenomenon happens:

https://hooktube.com/watch?v=DfPeprQ7oGc

(I'd forgotten about his emblem)

So I think it starts with the idea that subatomic particles, particularly electrons, really don't occupy "orbits" as per the Bohr model; it's more like a "cloud" of possible positions. I know that there's a certain tradeoff when it comes to measuring these particles–there's an actual name for it, can't quite remember…but the idea is that you really can't gauge the exact position of a particle without affecting its position…so the more accurate your determination, the less accurate it is compared to where the particle would have been had you not tried. I think this is the paradox behind all of the mysterious "Schrodinger's Cat" explanations–the cat really isn't there until you look. I think the act of "looking" is what is known as "wave collapse."

I don't know how "wave collapse" is aPost too long. Click here to view the full text.

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20b5b1 No.6140

HookTube embed. Click on thumbnail to play.

>>6139

whoops, forgot to include one of the best videos–guessing you've probably already seen it though.

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d06096 No.6152

>>6139

I'm glad to hear people are benefiting from it. I'm in university exam season at the moment, so once that's over I'll probably fix the mistakes and maybe update it with our other progress over the last few months. I certainly had more free time in December than I've had since, unfortunately.

>there's an actual name for it, can't quite remember

The uncertainty principle. I know probably as much about quantum computing as anyone else who has only really looked it up on the internet, but, as much as it has always been mentioned here in relation to the grid, I still see almost no parallels between the grid and quantum computing. It caused me a great deal of confusion back in November/December, to the point of distracting me from even figuring out how the grid worked entirely. If the same thing is confusing you (or anyone else who might read this), I suggest ignoring the quantum computing aspects for now. We're looking for some kind of mathematical relationship or principle that hasn't been officially and publicly discovered that allows you to do what Shor's algorithm does without needing actual qubits.

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File: d89730a2e148a59⋯.jpg (572.22 KB,1920x1200,8:5,0.jpg)

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2e6c6f No.5042 [Open thread][Last50 Posts]

I knew this would make a swastika eventually.

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ffd9d7 No.5858

File: ccb40c4610bf0bc⋯.jpg (159.93 KB,1600x1067,1600:1067,Fresh Bread 2.JPG)

>>5844

>5844

>>5844

>5844

>>5844

>5844

>>5844

>5844

FRESH BREAD HERE

Simple loaf, but delicious!

My first Bake.

Please post your favorite diagrams, or links to code. Batter was funky. I chose to err on the side of simplicity. Let's set up a pastebin for batter.

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ffd9d7 No.5859

Also, every Anon archive everything offline. I've got most of it, but need to save the maps first. Baker did a great job with that.

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8bba68 No.5860

File: 4facb29100bacd1⋯.png (382.81 KB,600x600,1:1,infinite.png)

Filling bread

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8bba68 No.5861

File: e586d6dda238007⋯.png (270.93 KB,500x375,4:3,vqc.png)

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7b70c2 No.5862

File: 0f384577dc861e6⋯.jpg (11.94 KB,255x149,255:149,30a1e7ecb8ff0f4b3debf17ef1….jpg)

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2bf75e No.4140 [Open thread][Last50 Posts]

The only thing you need to do to solve this is to organize.

Enumerate EVERY rule.

Global rules.

Row rules.

Column rules.

They are a finite set and RELATED.

This is your MAP.

You will be able to use the MAP to find n from c.

Enumerate the rules.

Win.

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4cf918 No.5063

File: 188d05566f49a53⋯.png (302.34 KB,500x282,250:141,All Your Base 1 copy.png)

>>5061

>>5062

Check Here? ;)

> "All your base are belong to us" comment somehow relates to the triangle base (u) in the small square formula.

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8298a2 No.5064

>>5063

I’m a bit slow!!!

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819f3a No.5065

PMA, we love you man. Just keep up the good work! Here's a good video for tonight.

https:// youtu.be/xFntFdEGgws

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8298a2 No.5066

>>5065

Thanks, VA. I think we all have made that leap of faith.

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1bfa60 No.5067

Filled

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e6d8c4 No.4253 [Open thread]

>>329715

>Well, if anyone associated with writing this is lurking, pop into the EZ Bake, plz…

not sure what I can do to Socrates here…will try.

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45c513 No.4317

What's this

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File: dde3c943519f5be⋯.jpg (115.06 KB,1680x1050,8:5,String-Theory.jpg)

File: e27beeedc9399c8⋯.jpg (31.9 KB,591x438,197:146,image.jpg)

File: 9703d0fe013898e⋯.jpg (15.77 KB,440x460,22:23,łoś.jpg)

add73d No.3361 [Open thread][Last50 Posts]

RSA General

Crumbs to focus on

In the (e,1) solution, d[t] = na+x

and a[t] = na

Therefore, if you can find the t value of this element, you can factor all semiprimes.

>Which column has NO gaps? [0]

>What is the pattern in COLUMN ZERO?

>One Row to Rule them All.

>A column that contains ALL and is the KEY to ALL the patterns.

>What are the patterns in COLUMN ZERO?

>If c is a semiprime, how many times does its square (c^2) appear in column zero? [5]

Why are there gaps?

The reason for the gaps may be because the VQC does not include decimal numbers. That is, because cells with gaps are the cells where the midpoint of a and b would not be a whole number. Or, worded another way, the difference between a and b would be an odd number.

There is a repeating pattern of gaps as you move horizontally from (0, n) to the right.

The pattern of gaps repeats every 2n if n is even.

The pattern of gaps repeats every n if n is odd.

>If first appearance of factor p is element t, second appearance will be at (p+1-t)

>p will be a factor of a in elements: t+p, t+2p, t+3p,

as well as in elements:

>p+1-t, 2p+1-t, 3p+1-t,

take d from all values of d[t] at (e,1) and there is a known pattern of (n-1) as factor in these values of d[t]-d that is different (increasingly) from the pattern of factors of n in aPost too long. Click here to view the full text.

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7fa95d No.4181

Another post

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7fa95d No.4182

Different words so I don't trigger flood detection

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7fa95d No.4183

Here's another post

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7fa95d No.4184

Text text text text text text text text text typing typing typing typing typing typing words words words

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7fa95d No.4185

.

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YouTube embed. Click thumbnail to play.

0eee92 No.1228 [Open thread]

To my favorite Faggot, VQC.

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b312ba No.1232

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993433 No.3577

And a Happy New Year!

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2dbaf3 No.2555 [Open thread][Last50 Posts]

Virtual Quantum Computer

Definition

The virtual quantum computer (VQC) is a grid made of infinite yet constructable sets that follow a known pattern. Like a quantum spreadsheet.

The grid is the superposition. The collapse of that superposition will be two input parameters, d and e which can be calculated easily for all integers, c, where c is the difference of two squares. Its purpose and our goal is to be able to factorize large semiprimes, all the way into the hundreds of digits, which would break the RSA cryptosystem.

When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows calculation instead of searching is possible.

Variables

The map's legend is {e:n:d:x:a:b}, where d is the result of removing the largest square from c AKA the square root,

e is the remainder,

n is what you add to d to be exactly halfway between a and b,

and x is what you add to a to make d.

c is any number that is the difference of two squares, so odd numbers are included. It is the number you want to factor.

f is what you add to c to make a square.

t is the third coordinate in the VQC..

Rules

Each cell of the grid (e,n) has infinite elements or ZERO elements.

Each cell with one value has infinite elements, since every element can make a new one.

By induction, a cell only needs one value to make infinite values, that's part of the power of this and is why it is a virtual quantum computer as a whole.

The t variable is what will allow you to walk across these infinite elements.

If a grid cell has elements, all elements are constructable from a finite set of root elements.

Post too long. Click here to view the full text.

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ab8fb8 No.3385

"The solution is a decision tree. The first decision is whether remainder is zero. The second decision is whether the remainder is odd or even. What's the third decision?"

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5167b5 No.3386

>>3385

Is this something VQC has said?

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738c11 No.3387

>>3385

The first decision is hardly a decision. Anyone knows that if e is zero then you have it factored, so why include this. This is included because he wants to make the 2nd decision about division by 2. Remainder is odd or even is also the same as asking what is the remainder upon division by 2. Then I'd say the third step would have to do something with the remainder upon division by 3.

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ff4dbe No.3388

>>3385

When did he say that? Link?

>What's the third decision?

At the top of the decision tree, if e = 0, it's a square, so it's not an RSA number (right?). If e != 0, we need to find n or x, which apparently relies on whether it's odd or even. In the second decision, whether it's even or odd determines what t is, but then to calculate t you need to know x, and if you knew x you'd know a. So do we know any other calculations that require knowing if e is even or odd? Otherwise, should we be using this to find relationships?

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ff4dbe No.3389

Last post so I can sticky the new one already

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2bad32 No.2943 [Open thread]

Howdy Pathgawds!

Along my musics, I found a someone who's working on a very similar thing from a different approach, but it's all related and nothing is coincidence.

That being said, he's a bit of a newfag, so to spare everyone his getting his own report thread, I'm just setting this up so that the RSA stays RSA and y'all can look into this if it piques your interest.

Dnimeerf, the floor is yours.

____________________________
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3f7a74 No.2959

That's nice of you. Hah. Freemind

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File: 0046244198028fd⋯.png (84.39 KB,250x250,1:1,anulowane.png)

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99fc86 No.1713 [Open thread][Last50 Posts]

Our task is simple. We are going to completely break the entire RSA cryptosystem! We're bigshots now.

But wait, how are we going to just crack RSA? With the Virtual Quantum Computer! Quick rundown to follow.

The main mathematical task that must be achieved to break RSA is to be able to factorize any integer instantly. The VQC is a promising way to do that.

What is the VQC?

The virtual quantum computer (VQC) is a grid made of infinite yet constructable sets that follow a known pattern. Like a quantum spreadsheet.

The grid is the superposition. The collapse of that superposition will be two input parameters, d and e which can be calculated easily for all integers, c, where c is the difference of two squares.

So, when the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows calculation instead of searching is possible.

Legend

The map's legend is {e:n:d:x:a:b}, where d is the result of removing the largest square from c AKA the square root,

e is the remainder,

n is what you add to d to be exactly halfway between a and b,

and x is what you add to a to make d.

c is any number that is the difference of two squares, so odd numbers are included.

n*a and n*b for any c can be found n places apart in the cell at (e,1).

Rules of the grid: global rules

Each cell of the grid (e,n) has infinite elements or ZERO elements.

Each cell with one value has infinite elements, since every element can make a new one.

By induction, a cell only needs one value to make infinite values, that's part of the power of this and is why it is a virtual quantum computer as a whole.

The t Post too long. Click here to view the full text.

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Post last edited at

99fc86 No.2551

>>2548

You can make it say someone spent their Bitcoin anywhere you want.

That counts as spending it, no?

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dbd176 No.2552

>>2551

Only when someone already spent some and you have their public key, so yes! Or if they try to spend it. No spending mined coins without a transaction first as far as I can tell

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96255b No.2553

File: 75def72be77e675⋯.png (50.79 KB,1359x315,151:35,active bans.png)

>>2476

It wasn't me. This is the only active ban (that person who was spamming "VQC's a shill, give up" sorts of posts). Maybe he was banned by a global mod (although they're only meant to do that if you post CP).

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b2f909 No.2558

>>2553

You're a good board owner.

Here's the new thread.

>>2555

>>2555

>>2555

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eb59f9 No.2559

>>2553

Disinfo is necessary

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File: 817cf4fd1dbf39b⋯.jpg (710.18 KB,2016x1512,4:3,calculating-F.jpg)

File: 8d8c74794f264a9⋯.jpg (717.32 KB,2016x1512,4:3,swapping-n-and-a.jpg)

File: 093fe5bc9cd55b6⋯.jpg (693.82 KB,2016x1512,4:3,(((Teach))).jpg)

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a2017c No.848 [Open thread][Last50 Posts]

Our task is simple. We are going to completely break the entire RSA cryptosystem!

And how are we going to do that?! With the VQC! Quick rundown to follow.

The main mathematical task that must be achieved to break RSA is to be able to factorize any integer instantly. The VQC is a promising way to do that.

What is the VQC?

The virtual quantum computer (VQC) is a grid made of infinite yet constructable sets that follow a known pattern. Like a quantum spreadsheet.

The grid is the superposition. The collapse of that superposition will be two input parameters, d and e which can be calculated easily for all integers, c, where c is the difference of two squares.

When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows calculation instead of searching is possible.

Legend

The map's legend is {e:n:d:x:a:b}, where d is the result of removing the largest square from c AKA the square root,

e is the remainder,

n is what you add to d to be exactly halfway between a and b,

and x is what you add to a to make d.

c is any number that is the difference of two squares, so odd numbers are included.

n*a and n*b for any c can be found n places apart in the cell at (e,1).

Rules of the grid: global rules

Each cell of the grid (e,n) has infinite elements or ZERO elements.

Each cell with one value has infinite elements, since every element can make a new one.

By induction, a cell only needs one value to make infinite values, that's part of the power of this and is why it is a virtual quantum computer as a whole.

The t variable is what will allow you to walk across these infinite elements.

Post too long. Click here to view the full text.
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8961b2 No.1736

>>1733

All is good, not posted much either since I'm little out of ideas and none of my attempts have gone anywhere. Still here banging my head against the grid with you!

Pretty sure I solved it in a dream already but not sure how. Doh.

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a92e07 No.1737

>>1735

I was having a really hard time with understanding what VQC meant when he said:

>At the correct element in the grid at (e,1) where the value of a at that element equals the na we want, if you subtract 2d+1 from na then you are in the negative half of the grid in terms of e and the value at the same element in the first row will be (n-1)a

I believe the "na" that we want refers to the na in the 2na = x^2 + e.

This is why I think the equation is important.

I'm trying to work out what the (n-1)a cell means now.

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537a7c No.1738

>>1733

Teach! Nice to see you!

>>1736

Nice to see you too, Anon!

>>1735

Well, if we’re able to solve for the small square using the t equations in row one that’s great! How do we tie that together with the column 0 knowledge? Or is it needed? If we know c, d and the small square, are we back to solving for n with the quadratic we derived? Column 0 still needs to get tied in? Thoughts, Anons?

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ac6203 No.1739

>>1737

Teach - likewise. I'm not sure I fully understand, but here's where my head is by way of an example:

c=145

1 x c => (1,61,6) = {1:61:12:11:1:145} = 145; (x+n)^2=72x72=5184; (d+n)^2=73x73=5329;

1 x c na => (1,1,6) = {1:1:72:11:61:85} = 5185; (x+n)^2=12x12=144; (d+n)^2=73x73=5329;

In the first record, calculate (n-1)*a = (61-1)*1 = 60.

If you look at the differences in the n, d, and a values between (1,61,6) and (1,1,6) you will notice:

n = 1

d = d + 60

a = a + 60

So essentially the amount you take off of n gets added into the d and a.

This "transform" enables us to move from any (e,n) into the (e,1) space, and explains what's happening to d and a along the way.

I have played with this attempting to take off different values from n. (n-2), 2(n-1), etc. Haven't had much luck there.

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537a7c No.1740

>>1733

Ah, nice Teach! There’s that clear relationship between n and x we’ve been looking for. Nice rewrite on the formula! We’ve been banging our heads on that for a while, I think you just made it crystal clear.

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File: ec07001c5cdac49⋯.png (46.22 KB,1200x710,120:71,Fermat's-Last-Theorem.png)

File: ac06802cb6173ef⋯.png (60.44 KB,1100x768,275:192,find-n.png)

File: 343d522b60d7374⋯.png (65.18 KB,2443x830,2443:830,geometries.png)

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ab77ef No.7 [Open thread][Last50 Posts]

General RSA thread. The next thread will have a properly formatted OP.

745 posts and 207 image replies omitted. Click [Open thread] to view. ____________________________
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64cf3f No.862

File: ade11a621c1856c⋯.png (438 B,58x36,29:18,hobosig.png)

>>822

Testing… 1…2…

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64cf3f No.863

File: 49cd5e5d40dc9b9⋯.png (358.71 KB,518x519,518:519,Melange.PNG)

File: 1e6b65486d3ee22⋯.png (505.87 KB,900x496,225:124,Dune.PNG)

>>850

Here is one for you Mr E Melange! The Memes must flow

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a96637 No.864

>>863

Thank you new Hobo friend! LOVE them, and perfect for our mission actually!

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0d970b No.877

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9ccc3e No.880

>>877

please see >>879

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File: 49e01f768e79b87⋯.png (139.36 KB,906x1788,151:298,49e01f768e79b87a0194c7f029….png)

File: 71165097878f9de⋯.png (2.09 MB,3036x2136,253:178,71165097878f9de538d22f995b….png)

File: bae310ebc4c7a15⋯.png (1.32 MB,4048x2848,253:178,bae310ebc4c7a15b8430e8df6a….png)

File: 65225adb5e1ae12⋯.jpg (1.92 MB,2544x3230,1272:1615,65225adb5e1ae12974896a2faf….jpg)

6fe83a No.1 [Open thread]

Rules:

1. No spam

2. Try to keep posts on topic. I'm not going to be a dick and ban everyone for dumb shit, but if you start a thread about shotacon or something, you're getting banned.

thebuttonnexttocapslocktwice@protonmail.com if it's ever necessary

____________________________
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6fe83a No.2

http://archive.is/zjUdO - VQC+++ postings

http://archive.is/bEVyM - RSA

http://archive.is/Kci21 - RSA #2

https://archive.fo/uEgOb - RSA #3

>>>/cbts/94250 - last /cbts/ thread - it isn't full, but if nobody posts there again here is an archive as of December 18 http://archive.is/eihrQ

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