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/vqc/ - Virtual Quantum Computer

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File: b061ef34289398e⋯.png (300.13 KB,500x282,250:141,All Your Base.png)

File: b174787910f6037⋯.jpg (1.28 MB,894x1180,447:590,AssangeyWarhaul.jpg)

File: 0c0e6de12efea63⋯.png (275.56 KB,733x744,733:744,RSA Tree.png)

File: 830a39e2ae9d917⋯.png (305.34 KB,333x500,333:500,WhenYouBelieve.png)

File: 81ba2295e21998e⋯.jpg (171.54 KB,600x444,50:37,Agartha 03.jpg)

33b02b No.8567 [Open thread][Last50 Posts]

The virtual quantum computer (VQC) is a grid made of infinite yet constructable sets that follow a known pattern. Like a quantum spreadsheet.

The grid is the superposition. The collapse of that superposition will be two input parameters, d and e which can be calculated easily for all integers, c, where c is the difference of two squares. Its purpose and our goal is to learn and show the TRUTH, one of them being P=NP. Cracking RSA will be a consequence.

When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows calculation instead of searching is possible.

Glossary

Column

All cells for a given e.

Row

All cells for a given n

The grid is indexed using e, n, and t, where e is the rows, n is the columns, and t is the specific element in the cell.

Entry, record, element

one set of variables that represents one factorization for a number.

an entry = {e:n:d:x:a:b} (e, n, t)

{1:5:12:7:5:29} (1, 5, 4) is a record AKA an element AKA an entry.

ab record, nontrivial factorization, prime record

the element that contains the factorization of c that is not 1*c, hence, nontrivial.

1c record, trivial factorization

the element generated from setting a=1 and b=c

Cell

All entries for a given e,n (not to be confused with an entry itself.)

Genesis cell

e,1

Remainder Tree

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bd2308 No.9413

File: 28bcdde0316060d⋯.jpg (41.89 KB,320x320,1:1,ea1106bc3c0076ed606b4f1d6b….jpg)

>>9412

Factoring c is easy when you're a faggot. ;)

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bd2308 No.9414

File: a808edf2f8e5875⋯.jpg (625.44 KB,975x975,1:1,b361c127de0e5b01df0bab610a….jpg)

nom nom nom nom nom

bread.

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bd2308 No.9415

File: 4f575a2b151ff96⋯.mp4 (12.31 MB,720x406,360:203,4f575a2b151ff964a66267a4a0….mp4)

This is solid

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a3e291 No.9416

Filling the thread

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a3e291 No.9417

Bloop

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File: a4bfd8f4ee7402c⋯.jpg (71.29 KB,363x225,121:75,oldBreadRehash.jpg)

a1d7a2 No.6210 [Open thread]

This thread is for the purpose of examining old breads, for those of us starting late. This will allow us to work without detracting from the main RSA threads, and hopefully help us to catch up sooner rather than later.

Here are links to archives from /cbts, and older breads–you'll find relevant links in all of them:

RSA #0 —— https://archive.fo/XmD7P

RSA #1 —— https://archive.fo/RgVko

RSA #2 —— https://archive.fo/fyzAu

RSA #3 —— https://archive.fo/uEgOb

RSA #4 —— https://archive.fo/eihrQ

RSA #5 —— ,>>7

RSA #6 —— ,>>848

RSA #7 —— ,>>1713

RSA #8 —— ,>>2555

RSA #9 —— ,>>3361

RSA #10 —— ,>>4140

RSA #11 —— ,>>5042

RSA #12 —— ,>>5844

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70d884 No.7359

File: f89d1514e885919⋯.png (114.98 KB,1920x780,32:13,nEqualsJminusD.PNG)

File: 25293bb046cf8ab⋯.png (9.17 KB,642x146,321:73,extendingTheGrid.PNG)

So rather than start up with the imaginary plane, I've been working on extending the Grid upward. I could swear I've seen a few images where that has been done already, but I haven't relocated them yet and I don't remember the method being posted.

Chris recommended that we extend it upward where 'x' becomes negative. For that to happen, 'a' would have to be larger than 'd', since

x = d - a;

The way I've read his direction, it seemed as if the imaginary plane was to occupy the 'z' axis–extending out toward the viewer from the flat surface of the screen. So I was making an effort to keep 'c' positive for this base grid. A while back, I'd considered the effects of making both 'a' and 'b' negative:

-a = j - i;

-b = -j - i;

Since a * b = -a * -b, we'll end up with the same 'c', which we can take a real root from. However, that wouldn't give us a negative value for 'x'; in fact, it would make it even more positive:

x = d - (-a); // = d + a

So we're stuck with many options, if we want to keep this base grid 'real' (which may not even matter). We can:

1) redefine 'd' for the upper half of the grid, to give a result smaller than 'a'

—this might not be such a bad idea, since we did add 1 to 'd' for rendering 'f' side values

2) swap 'a' with 'b', because 'b' will always be >= 'd'

3) redefine 'x' to equal 'a - d' for the upper part of the grid

4) set an iMin < 0

5) solve for 'c' = -c, and let the upper half of the grid represent only the 'real' part of the complex root

—you can't well have x = (some complex root 'd') - a, unless you want a complex 'x' answer.

Our requirements are that n <= 0, and x <= 0.

Each of these options has ramifications. Most importantly to me, the answers shouldn't break the existing equatioPost too long. Click here to view the full text.

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70d884 No.7360

>>7359

Note that I don't think this is the way to illustrate the 'prime object' that we're working towards. I think the upper part of the grid should represent the real parts of the complex roots when we solve for -c, although I'm not quite there yet. But graphing 'n' = j - d extends our understanding of what's going with each value 'c'; it shows us how far both 'd' and 'd+1' are from that fourth important square, j^2.

It's also trivially easy to find the first one: for each prime or semiprime along the 'bigN' diagonals, they're one cell up.

So, let's call the 'n' = j - d value 'nu', for 'n upper'.

For each prime, there is one occurrence in the column. For each semiprime, there are two: one just above the normal one in the 'bigN' diagonal, and another one located above the second normal one (the one that holds the factored 'a' and 'b'. This second 'nu' cell also contains the factored 'a' and 'b' values; if we can find a way to get to this cell, we will have found our two prime factors. Thus, we have just doubled our possible routes to success ;)

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70d884 No.7361

File: 7d0c76294fa0411⋯.png (93.43 KB,1920x707,1920:707,Capture.PNG)

File: 0c5c222b7219f84⋯.png (109.48 KB,1918x732,959:366,Capture1.PNG)

>>7360

So Bitchute isn't exactly reliable unless someone is seeding, and I don't feel like seeding at the moment. I don't want to upload to youtube b/c we all know how Google has been ever since they lost their idealism. So I'm uploading the video here:

https://ufile.io/hsp8d

it will stay up for 30 days; I'll repost again later after that.

First pic related is the grid showing only values generated by setting nu = j - d. Second pic has n = i - d, and nu - j - d values. iMax was set to 128 here.

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70d884 No.7379

File: b57f9598500b50a⋯.png (68.93 KB,1920x531,640:177,filterElessthansqrtIMaxplu….PNG)

I thought this was cool.

setting 'e' and 'f' as usual, then using n and nu, I plotted four t values for every difference of squares i^2 - j^2:

(e,n), (f,n+1), (e, nu), (f,nu+1)

Then I filtered for the center part:

int emax = sqrt(iMax) * 2 + 1;

int fmin = -emax;

if(e <= emax || f >= fmin){

{…add values to cells}

The idea is that if a value is created that would land in the center region where the spiral would be, all other related values will be stored as well, regardless of whether or not they're in that region. So you get every prime and semiprime that would lie along the bigN diagonals, but you also get the columns above (where some of the nu semiprimes reside). It's interesting that it renders to this kind of angelic, four-winged shape was surprising–thought I'd share :)

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3d223c No.8933

File: a94671f63f02b34⋯.mp4 (1.6 MB,1912x1080,239:135,GridFill_VQC_PrimeAnon.mp4)

>>7279 some great work here by PA.

Attached is mp4 grabbed from the link that can readily be saved offline.

Was doing something similar, adding a "Sequence" counter to the inner-loop of the original VQC algorithm and then looking at how the sequence changed based on sorting other variables in the resulting list of elements.

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File: c807fd017a9e425⋯.png (5.04 KB,341x213,341:213,math.png)

File: 0c522d560fc1207⋯.jpeg (63.29 KB,1280x720,16:9,225.jpeg)

72180a No.7690 [Open thread][Last50 Posts]

The virtual quantum computer (VQC) is a grid made of infinite yet constructable sets that follow a known pattern. Like a quantum spreadsheet.

The grid is the superposition. The collapse of that superposition will be two input parameters, d and e which can be calculated easily for all integers, c, where c is the difference of two squares. Its purpose and our goal is to learn and show the TRUTH, one of them being P=NP. Cracking RSA will be a consequence.

When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows calculation instead of searching is possible.

Glossary

Column

All cells for a given e.

Row

All cells for a given n

The grid is indexed using e, n, and t, where e is the rows, n is the columns, and t is the specific element in the cell.

Entry, record, element

one set of variables that represents one factorization for a number.

an entry = {e:n:d:x:a:b} (e, n, t)

{1:5:12:7:5:29} (1, 5, 4) is a record AKA an element AKA an entry.

ab record, nontrivial factorization, prime record

the element that contains the factorization of c that is not 1*c, hence, nontrivial.

1c record, trivial factorization

the element generated from setting a=1 and b=c

Cell

All entries for a given e,n (not to be confused with an entry itself.)

Genesis cell

e,1

Remainder Tree

The remainder tree is the resPost too long. Click here to view the full text.

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Post last edited at

81cdd5 No.8595

File: b30fb45c4b6af95⋯.png (302.95 KB,1087x1049,1087:1049,VQCMathsAsOf2192019-Fixed-….png)

>>8594

-shrug-

The interaction got VQC's attention for the crumbs.

Fixed.

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81cdd5 No.8596

File: 9e91f055294a635⋯.jpg (1.24 MB,2266x1164,1133:582,WhenDoTwoParallelLinesMeet.jpg)

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344e49 No.8599

Filling the thread

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344e49 No.8600

1+1=2

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344e49 No.8601

0+0=27

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File: 0b14903109a5612⋯.jpg (21.95 KB,317x317,1:1,mobiuspmaze.jpg)

25b5b6 No.5913 [Open thread]

http://archive.is/rVPNi

http://archive.is/AbPty

http://archive.is/PHCob

http://archive.is/Cfp0S

http://archive.is/K9ipC

mass and mass has energy or energy and energy has mass

or all mass is imaginary

rest mass

rest energy

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d7ecb8 No.7896

http:// empslocal.ex.ac.uk/people/staff/mrwatkin/isoc/psizoom.htm

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d7ecb8 No.7897

http:// vixra.org/pdf/1511.0239v1.pdf

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d7ecb8 No.7898

https:// eujournal.org/index.php/esj/article/viewFile/7488/7212

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8e77f2 No.8465

>>6393

Find the Y.

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8e77f2 No.8466

File: e5d3e103719526a⋯.png (129.51 KB,1280x1024,5:4,20181215_204952.png)

>>7296

Find the Y

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File: 15df4030f03903e⋯.png (103.11 KB,1270x1224,635:612,Screen Shot 2017-12-30 at ….png)

f210ba No.1762 [Open thread][Last50 Posts]

>>1672

Since this is exactly what we don't want to be doing, I created a seperate thread for it. Also I don't have the batter for the other one. I'll probably jump back into the new thread once it is created.

I have devised a way to generate the (e,n,d) coordinates for any d value. This requires new rules. For now, I'm ignoring the x,a,b,c values because they aren't required for this pattern. That said, if we analyze steps of this pattern we may have patterns in x,a,b,c, I just haven't checked yet. I'm still trying to validate if this is the case. Also, for this, you generate (e,n,d,x,a,b,c) values through END(e,n,d) which is posted in my other code dump

(E,N,D,O,T)

Pic related is for D = 6.

On this graph, the +'s indicate a value that was generated by theend(1500) code. The *'s indicate a suspected d at that value. Whether or not the *'s actually correspond to a cell we can overlook for now, because the pattern seems to hold.

O is the origin cell of a line. Indicated by the integers in the chart (except for the 6,7,8,9 on the line). 0 is the zero origin, 1 is the 1 origin etc.

For each origin cell, the value of T is 0. For the cell on the N+1 row relative to an origin line, we have T = T+1. The T's for O=1 are written for T=6,7,8,9

Now that you can read the values, here are the rules I've discovered:

(-D^2, -D, D, 0, 0) is a valid start record for any D

(e,n,d,o,t) -> (e+t^2, n, d, o+t, 0) (to generate origin cell for same row given any cell)

(e,n,d,o,t) -> (e+2o, n+1, d, o, t+1) (to get next t) *

(e,n,d,o,t) -> (e-2o, n-1, d, o, t-1) (to get prevoius t) *

(e,n,d,o,0) -> (e+2ot, n+t, d, o, t) (any t from origin) (basically the same as the two * above)

(e,n,d,o,0) -> (e-t^2, n, d, o-t, t) (to generate other cells in row n from t=0) (t<o)

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d039eb No.7786

File: a2b6c66ce880199⋯.png (28.98 KB,1240x876,310:219,pic_31.PNG)

Still f = -40

from % - 5 we can see one larger parabola.

The origin of this parabola is at (e,n) = (43, 11)

Then e shifts by 4 each time you go down the parabola and n shifts in square amounts.

As you go around these parabolas, the a values all stay the same, and the b values change

in amounts of 2*(2k+1) but they are centered at e=43 the origin line and aren't related

to their position the the parabola relative to n.

As you zoom around the parabola, d and x both increase by 2 and a stays the same.

The inner parabola is centered at (e,n) = (41, 21)

You can see from this parabola, that the increase x by two pattern stays,

Also the t values increase by one. a and b and d+n and x+n all kind of are the same from 7 to 8

and I think that is because they go around the origin axis, whereas the last parabola hit the axis.

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d039eb No.7787

File: 9c9aa3df5482fee⋯.png (29.56 KB,1153x865,1153:865,pic_32.PNG)

It might be hard to tell from this picture, but the origin of this bigger hyperbola for f=-60

is at (e,n) = (59, 1). It always seems to be at (-f-1,1).

From here, you can see the larger inner parabola has its origin at (e,n) = (63, 16)

and it has a inner parabola with the origin at (e,n) = (61, 31)

So how do these coordinates work? The bigger parabola starts at e = origin_e + 4, n = origin_n + f/4

The smaller parabola is at e = origin_e + 2, n = origin_n + f/2

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d039eb No.7788

File: 3f41ac013962d6a⋯.png (24.98 KB,1063x879,1063:879,pic_33.PNG)

Here is f = -42. Notice how unlike the last two this one does not have the bigger parabola, just the smaller one.

That is because f is not divisible by 4, so we couldn't do (n= origin_n + f/4), but it is divisible by 2.

Of course, since this is an f grid, the origin is located at (42-1,1) = 41,1.

Then there is obviously, near the bottom, the parabola which represents it's divisibility by 2.

It's origin is at (e,n) = (43, 22) which is (origin_e + 2, origin_n + 42/2)

This has values that co around similar to the last one

BUT now look at #6, where (e,n) = (47, 8). This is also (origin_e + 6, + origin_n + 42/6)

Crazy enough this works for every single factor.

For each parabola, the amount with which you shift is scaled also. For instance the #6 to #7

transition, relative to a normal parabola would be a (e+1,n+1) shift, but here it is being shifted

like (e+12, n+6), which is just (e+2m, and n+m) where m is the factor of f.

So in theory every factorization of every number would have cells organized like this in the f grid.

I think we could use our f value and factor it to find similar entries along this f grid.

Once you notice that this works for every factor its easer to see that this hyperbola is just made of a lot

of stretched out parabolas.

Thats all I got for now. Peace.

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d039eb No.7791

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27ba6c No.8038

File: 9e7567dbc883f91⋯.png (797.64 KB,4000x4000,1:1,A_Grid_Complete.png)

File: 4c8883389666f17⋯.png (645.77 KB,3946x3471,3946:3471,X_Grid_Complete.png)

Some Grids analysis I've done

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File: 3a64681aeeaac8d⋯.png (137.09 KB,530x370,53:37,serveimage.png)

File: 8a9bbd8a6c81fe7⋯.gif (14.89 KB,300x250,6:5,serveimage.gif)

File: 763a244986bc9f8⋯.png (2.68 MB,7000x3780,50:27,763a244986bc9f8d61d9cb33a5….png)

File: 09af00d0692a6d9⋯.png (827.14 KB,2533x1826,2533:1826,09af00d0692a6d9261ed5ba39a….png)

File: 4a1653e4ef1564e⋯.jpg (551.81 KB,1200x850,24:17,68665783_p0_master1200.jpg)

868475 No.6694 [Open thread][Last50 Posts]

The virtual quantum computer (VQC) is a grid made of infinite yet constructable sets that follow a known pattern. Like a quantum spreadsheet.

The grid is the superposition. The collapse of that superposition will be two input parameters, d and e which can be calculated easily for all integers, c, where c is the difference of two squares. Its purpose and our goal is to learn and show the TRUTH, one of them being P=NP. Cracking RSA will be a consequence.

When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows calculation instead of searching is possible.

Glossary

Column

All cells for a given e.

Row

All cells for a given n

The grid is indexed using e, n, and t, where e is the rows, n is the columns, and t is the specific element in the cell.

Entry, record, element

one set of variables that represents one factorization for a number.

an entry = {e:n:d:x:a:b} (e, n, t)

{1:5:12:7:5:29} (1, 5, 4) is a record AKA an element AKA an entry.

ab record, nontrivial factorization, prime record

the element that contains the factorization of c that is not 1*c, hence, nontrivial.

1c record, trivial factorization

the element generated from setting a=1 and b=c

Cell

All entries for a given e,n (not to be confused with an entry itself.)

Genesis cell

e,1

Remainder Tree

The remainder tree is the resPost too long. Click here to view the full text.

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d4c3ed No.7685

So we have (e * nn, n) and (e + nn, n), both of which extend or transform the records in some way.

(e * nn, n) will extend the sequence (Essentially increase the number of sequences in our row) while (e + nn, n) will transform / modify our row by exchanging values of d, x and a with other values. I'm going to try and think more about what this actually means and try and formulate a better description of what actually is happening. I'm struggling a bit with visualizing what I'm doing, so I would like to try and step back a bit to get a better understanding of why (e + nn, n) and (e * nn, n) works the way they do.

As for (e * nn, n) we will see repetitions of (1, 1) in every (nn, n) as 1 * nn = nn, meanwhile this explains the repetitions of (0, 1) in (0, nn).

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d4c3ed No.7686

>>7684

Regarding the fractal / mandelbrot idea I'm wondering if that's actually our fractal. As in, (0, 1) or (1, 1) is the "base" mandelbrot set, as in the grand picture and why VQC has been telling us to use bigger numbers. Because by doing so we'll start seeing the repeated numbers.

I'm just spitballing, so I'm probably way off, but I can't help but shake the fact that our equation for c (d^2 + e) is exactly the same as the one for mandelbrot (z^2 + c).

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d4c3ed No.7687

>>7686

In the mandelbrot set you have a term called "escaping" in which a point that is "escaping" means that the point is not within the boundaries of the fractal (If I grasped it correctly). I wonder if prime numbers are the ones that "escape".

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64f02a No.7688

Fibonacci autist here.. This might be really fucking important. I need to test something. I need a couple of large sub-prime numbers that I do not know the factors to. Fucking pronto.

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412edb No.7689

>>7688

>guys I totally actually figured it out this time, spoonfeed me

My ass. 22222268356688393753

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File: c0d48023082c3e7⋯.png (154.68 KB,1280x1024,5:4,multiD ARC iteneration 2.png)

a1ef3b No.7303 [Open thread]

Vqc Is a Multidimensional Grid that explains the TOE

4 posts and 1 image reply omitted. Click [Open thread] to view. ____________________________
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a1ef3b No.7339

File: 493138d9d2c8fbc⋯.png (120.52 KB,1280x1024,5:4,innersqr41.4.png)

File: 92cca1d519b0c91⋯.png (70.52 KB,1280x931,1280:931,finishinnercircle.png)

File: 0bbcccb082da3e3⋯.png (68.9 KB,1280x940,64:47,innercirc2a.png)

File: 24d1fe332f27970⋯.png (121.12 KB,1280x1024,5:4,innercirc2b.png)

File: 097d57a8ab5df1f⋯.png (81.66 KB,1280x949,1280:949,innercirc2c.png)

Someone in RSA wanted to define the inner circle of a triangle. So I did. And while doing that I realized that the shift from 30 degree rectangle, to 45 to 60 is the same figure that vqc gave us all. Then as I figured the inner circle I realized it is a scale shift as in fractal and Mandelbrot.

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a1ef3b No.7345

File: e9a1b40e795013b⋯.png (8.16 KB,512x84,128:21,512px-Sierpinski_triangle_….png)

File: e2244ba15c9dee8⋯.jpg (11.96 KB,259x194,259:194,mand1.jpg)

Cross Post:

>Can you actually get a fractal out of a regular geometric figure?

Yes and no.

sierpinski triangles are regular real fractals. Mandelbrot is plotted in the imaginary plane (sqrt of -1) and iterations that remain level are black those that arc to infinity are colored (not in set). To try and get real geometric figures to Mandelbrot will probably depend upon the number of iterations or the actual value per iteration. But each iteration may be a 90 (or other) degree shift from the 4D plane.

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a1ef3b No.7351

YouTube embed. Click thumbnail to play.

Lie 8 group.

what if all those lines are radii?

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a1ef3b No.7373

File: 64cb52cfe75c1ea⋯.jpg (6.58 KB,225x225,1:1,lieanim4.jpg)

File: 41816fcd11bd2c7⋯.png (255.63 KB,1600x1200,4:3,witting8b_lattice_dd_2-3-6….png)

File: 3d589e905cf4652⋯.jpg (22.67 KB,284x177,284:177,mandelbrotout.jpg)

>>7351

The Mandelbrot Set could possibly be a geometrical projection of the Lie 8 group.

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a1ef3b No.7374

File: ea1a48882da906f⋯.png (60.06 KB,250x226,125:113,250px-Hopf_Fibration.png)

>>7373

If you are projecting a geometric figure not onto a flat plane but a tilted or warped plane it will alter the image. My question next would be is if you project onto a hypersphere? such as above or the Hopf Hyper Sphere (which is simpler than the one above).

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File: 52d4fd57c143256⋯.png (47.9 KB,4096x2048,2:1,output.png)

f51d54 No.356 [Open thread]

I have to address this because people are reporting him. What do we do about Topolanon? Some of you don't mind him and some of you want him banned. We haven't discussed specific rules as a group yet so I can't just use my own discretion.

44 posts and 21 image replies omitted. Click [Open thread] to view. ____________________________
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4ec760 No.741

File: 8c63de592655458⋯.png (361.75 KB,1059x795,353:265,no.png)

>>740

>ban pon-

how could you?!

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9dc20e No.745

>>740

I'm in agreement with VA. Didn't throw opinion out there earlier, as I think those doing the heavy lifting and bulk of work should have a stronger voice, but maybe that is anathema to anon and all voices are equal, dunno.

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f51d54 No.798

>>740

>should we ban ponies too

For the love of god please they're fucking cringeworthy but I feel too outnumbered to say it

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4ec760 No.823

>>798

I'm gonna love and tolerate you

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bae151 No.7242

File: 83056ddfb32d7f6⋯.png (355.32 KB,923x644,923:644,DoABarrelRoll.png)

>>445

One thing that has always been in the back of my mind is that this conversation had to do with VQChris and RR!Quinn Michaels being in on this conversation… with Quinn being the "demoralization shill".

Weeeeeeell…

Now ebot is seeming to nod a certain way…

As if it's… ebot… ebrother of #Tyler.

Granted, Quinn's main schtick is aggregation, repackaged, as most of his storyline comes about from him derping around online and stringing things together as he finds them.

Quinn was stuck in a hospital for the majority of this and I stopped hearing much about him after Jason Badman fell out my awareness.

Granted…

Quinn and Defango were almost obviously tag teaming Jason.

First Jason attached onto George Webb and Trish was… there.

Defango shows up… derail.

Supposedly there was a message from Defango at the time Quinn's lung got collapsed…

It's taken care of.

Defango wrote a thingy about VQC back in the formative days.

Dot dot dot…

Connections…

Reconcile.

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File: 0de58d13ef0a0be⋯.png (72 KB,1258x873,1258:873,Intro-to-ECC-1.png)

File: fa98864e8764849⋯.png (50.79 KB,1200x710,120:71,Discrete-Logarithm-Problem.png)

File: eedf4a87f63e3c6⋯.png (261.9 KB,2573x2086,2573:2086,Diffie-Helmann-Key-Exchang….png)

File: 61526f074a1c9cb⋯.png (768.98 KB,755x1021,755:1021,Baker's-Perfect-Math-Class.png)

c0824e No.7187 [Open thread]

ECC starting from the basics.

If you can understand what mod means,

if you can understand graphing points,

if you can understand arithmetic,

if you can understand logarithms,

You can understand ECC. Maybe you'll even get to see how they're modular forms..

and what a modular form is.

I will walk through it from start to finish. I'll start by listing the prerequisites to ECC. There aren't many. A novice can understand.

Logarithms

All a logarithm is, is calculating n in picture 2, where b and x are given. The following articles and the 2nd picture should clarify.

https://www.mathsisfun.com/algebra/logarithms.html

https://simple.wikipedia.org/wiki/Logarithm

The Discrete Logarithm Problem

So now that we have established what a logarithm is, then we can understand this easily. The Discrete Logarithm Problem (DLP) is the problem of calculating n in bⁿ = x, where we know b and x. Aside from certain cases (which do not apply to where you encounter them in cryptography), there is no known efficient method for computing this.

Diffie-Helmann

https://youtube.com/watch?v=YEBfamv-_do

https://youtube.com/watch?v=ESPT_36pUFc

https://youtube.com/watch?v=Yjrfm_oRO0w

These videos and picture 3 should clarify how the Diffie-Helmann cryptosystem uses the DLP to encrypt, decrypt and sign messages.

Galois Fields

Will be explained in the next posts.

EC Arithmetic

Will be explained in the next posts.

____________________________
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c0824e No.7188

File: 9d5214ae19572a8⋯.png (93.96 KB,1210x333,1210:333,Screenshot from 2018-08-10….png)

Extra: an interesting thought.

>both are cases of a hidden subgroup problem in Abelian groups.

Why was it trivial for mathematicians to extend Shor's algorithm and sieving algorithms (factorization) to solve the DLP?

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c0824e No.7189

Java code that will be useful later:


public static int legendreSymbol(BigInteger a, BigInteger p) {
BigInteger pm1 = p.subtract(BigInteger.ONE);
BigInteger ls;

ls = a.modPow(pm1.divide(BigInteger.valueOf(2)), p);

if (ls.equals(pm1)) {
return -1;
} else {
return ls.intValueExact();
}
}


public static BigInteger modSqrt(BigInteger a, BigInteger p) {
a = a.mod(p);

if (legendreSymbol(a, p) != 1) {
return zero;
} else if (a.equals(zero)) {
return zero;
} else if (p.equals(two)) {
return p;
} else if (p.mod(four).equals(three)) {
return a.modPow(p.add(one).divide(four), p);
}

BigInteger s = p.subtract(one);
int e = 0;

while (s.mod(two).equals(zero)) {
s = s.divide(two);
e += 1;
}

BigInteger n = two;
while (legendreSymbol(n, p) != -1) {
n = n.add(one);
}

BigInteger x = a.modPow(s.add(one).divide(two), p);
BigInteger b = a.modPow(s, p);
BigInteger g = n.modPow(s, p);
int r = e;

BigInteger gs, t;
int m;
while (true) {
t = b;
m = 0;

for (; m < r; m++) {
if (t.equals(one)) {
break;
}

t = t.modPow(two, p);
}

if (m == 0) {
return x;
}

gs = g.modPow(two.pow(r - m - 1), p);
g = gs.pow(2).mod(p);
x = x.multiply(gs).mod(p);
b = b.multiply(g).mod(p);
r = m;
}
}

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c0824e No.7190

nistp256 {

p = 115792089210356248762697446949407573530086143415290314195533631308867097853951

#G = 115792089210356248762697446949407573529996955224135760342422259061068512044369

a = -3

b = 41058363725152142129326129780047268409114441015993725554835256314039467401291

Gx = 48439561293906451759052585252797914202762949526041747995844080717082404635286

Gy = 36134250956749795798585127919587881956611106672985015071877198253568414405109

}

secp256k1 (Bitcoin Curve) {

p = 115792089237316195423570985008687907853269984665640564039457584007908834671663

#G = 115792089237316195423570985008687907852837564279074904382605163141518161494337

a = 0

b = 7

Gx = 55066263022277343669578718895168534326250603453777594175500187360389116729240

Gy = 32670510020758816978083085130507043184471273380659243275938904335757337482424

}

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c0824e No.7206

File: 276e3e7a43442e3⋯.png (100.63 KB,1359x454,1359:454,Screenshot from 2018-08-10….png)

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File: 8a684100972667a⋯.png (962.12 KB,1366x768,683:384,Screenshot from 2018-01-05….png)

23d5bf No.2563 [Open thread]

Would anyone be interested in some explanation of what "occultism" means and how all of this spooky stuff people have been alluding to works? I know at least several if not most of you have expressed a belief in the idea that we as a group of people were meant to come together as we did (Chris included), but for most it seems to just be to the point of knowing that there's more to what's going on than we're aware (likely in part because of some of what Q has said). Of course, maybe some of you even know more than I do. That said, I've been studying, reading etc for the last three years, and I feel I know enough that I could shed light on some important things, such as reasons to believe consciousness isn't physical, how Kek works, how reality works in relation to this stuff, etc.

I'm well aware that, from an outsider's perspective, whenever most of you have read about this kind of thing, you probably thought it was stupid, meaningless word salad with no practical application. That was me before I delved into it (I was an agnostic atheist). I've always tried as hard as possible to understand the theory behind things, rather than being one of those people who says "namaste" all the time and regurgitates useless bullshit like "you need to raise your vibration and become one with the universe, man; open your third eye" without understanding anything. You can all easily find this information by scouring the internet (there are even a few boards here, such as >>>/fringe/, although the board culture there is discouraging), but if anyone would like, I could explain stuff like pic related (something Chris retweeted), answer questions, provide books (I have thousands) and point people in the right direction.

13 posts and 5 image replies omitted. Click [Open thread] to view. ____________________________
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a954a7 No.2722

>>2721

Tulpa

Do you?

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23d5bf No.2725

>>2722

No, I really don't want a tulpa. Why would I want something siphoning away my loosh all day and needing attention? I have way too much shit to do. Also it seems like we have different understandings of the word thoughtform. All tulpae are thoughtforms but not all thoughtforms are tulpae. They aren't interchangeable words.

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a954a7 No.2728

>>2725

Yeah, you need some time of your own. It gives you new abilities though.

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23d5bf No.3036

I don't know if anyone's actually interested in it but I still intend to continue this thing. I've been busy.

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a738f5 No.6953

https:// books.allatra.org/allatra-online-en/?page=1

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File: fce8c440feb788f⋯.jpg (101.86 KB,500x332,125:83,alsea 4.jpg)

File: 9a7ad96b5270b0c⋯.jpg (85.47 KB,640x427,640:427,alsea 2.jpg)

File: 1da6c45cbb0d715⋯.jpg (316.33 KB,1100x731,1100:731,alsea 3.jpg)

File: 9845723e0091254⋯.jpg (87.88 KB,640x427,640:427,alsea1.jpg)

02fbf9 No.4552 [Open thread]

So, like any good hobo I have been around. Also, I have done some camping. A few people talked about meeting up and camping would be a good way to do it. Its cheap. Its fun, Its public, and its different.

So my favorite place to camp is Western Oregon. I never miss a summer out that way and this year is no different. So I hereby propose a math camp for everyone here.

To really make it happen we will need a chunk of time that everyone can make it. My window is from May through Aug. I recommend Late May/early June as this is the best weather, and minimal chance of us getting smoked out… Well smoked out from forest fires.

I will be in the area with all my shit for camping so it will be easy for me to set it up more or less and I can do transportation from either Portland or Eugene Airports. Portland is kinda far though so I would like to make just one trip there if possible.

Coordination will the the hard part so lets start with dates., Post your dates below and lets see what lines up..

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3f8623 No.4564

Thanks Hobo! I'm checking in. Great photos, making me hungry for the woods.

“I went to the woods because I wished to live deliberately, to front only the essential facts of life, and see if I could not learn what it had to teach, and not, when I came to die, discover that I had not lived. I did not wish to live what was not life, living is so dear; nor did I wish to practise resignation, unless it was quite necessary. I wanted to live deep and suck out all the marrow of life, to live so sturdily and Spartan-like as to put to rout all that was not life, to cut a broad swath and shave close, to drive life into a corner, and reduce it to its lowest terms…”

― Henry David Thoreau

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02fbf9 No.4567

My window is from May through Aug.

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3f8623 No.4568

https:/ /youtu.be/j64SctPKmqk

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02fbf9 No.4570

>>4568

never been much for poetry but I like a good story.

So a farmer's horse ran away. All his neighbors came to him and expressed their sorrow at his loss. He was unperturbed and simply replied. May be,May Be.

The next day the farmers horse returned followed by 2 wild horses! The farmers neighbors returned and cheered! You are so lucky they said. May be, May be.

The very next day the farmer came out of his house and his son was trying to break one of the new horses to the saddle. As a small crowd formed, the horse suddenly bolted throwin the farmers son off his back. He landed hard and broke his ankle, Oh, no we are so sorry for your loss they said to the farmer. May be, May be, he replied.

A few weeks later the farmer was called to the center of the village by the village bell. He and his son, now on crutches, went. There were military men from the capitol recruiting for a new and bloody war in the far north. The soldiers passed the farmers son by because he could not walk on his broken ankle… They instead took all his horses…

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1494ec No.6845

>>4552

I'm digging on this idea, but it will be awhile before I can commit–like maybe 2-3 years. I'll be in college, then (hopefully) working…but looking at your images, or any images like them, just stirs something deep inside.

I love getting out as well, though I haven't camped in many years. Most of my hobbies have to do with getting out into nature, but not just for looking—I forage as well. Rockhounding, mushroom-hunting, that kind of thing.

Not sure where I'll find work; hopefully outside of California. But yeah–I love getting out into the wilderness. Nothing like it.

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File: 2ad908e903f8e7e⋯.png (176.23 KB,270x343,270:343,Can I Haz P=NP.png)

File: 609ad2038edc987⋯.png (548.11 KB,1523x380,1523:380,Screen Shot 2018-05-07 at ….png)

File: 39c906a1fac5de8⋯.png (36.1 KB,1916x1154,958:577,c=6107 PMA.png)

File: c0ed063ff530239⋯.png (22.78 KB,795x797,795:797,Screen Shot 2018-05-07 03.png)

193f3e No.5844 [Open thread][Last50 Posts]

VQC sez: "(You) are at The final lock and key construction steps. Happy to give it but it is the Eureka moment and anons are close. In hindsight, it shows exactly why this problem has existed for so long.You are solving two problems at once in this method of constructing the answer. Also in hindsight the steps give the pattern back in the grid (The End).

746 posts and 427 image replies omitted. Click [Open thread] to view. ____________________________
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cf67c1 No.6742

When at least one regular or two anons confirms they are happy with the constructibility of cells to be zero or infinite in elements, we'll move on.

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5a1919 No.6743

>>6741

Y'know… I don't think Baker will mind since you're the one who set it up.

The one we had prepped is the one with the 145 as the image.

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b89382 No.6744

File: 11125e765e120ae⋯.gif (972.92 KB,312x213,104:71,it's happening.gif)

>>6741

We already had one, actually. Baker made one >>6694 here. We could use yours instead if you're doing more specific coordination right now. Baker probably won't mind.

>>6743

Oh hey, hive mind. Hello Topol. Did you see what I put at the top of this post? >>6717

>>6742

I don't need proof by induction personally. There are infinite sets of (e,n), within each (e,n) there either aren't any elements or there is an infinite set of elements, and you can go from one t index of that (e,n) to the next with the formulae for creating a new endxab. So that's confirmation from at least one of us.

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5a1919 No.6745

>>6744

Missed that.

That is interdasting…

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cf67c1 No.6746

>>6744

>>6744

Great, feel free to delete the new one.

Thanks for the confirmation.

Next, we show how to calculate BigN of an odd number.

All odd numbers are the difference of two squares.

The product of two primes, is the difference two sets of squares.

Every odd number is the difference of two consecutive squares.

The value of n for the product of 1 and c is defined now as BigN for odd numbers.

Since d-a=x and x+n is the smaller square in the difference of two squares, then for odd numbers, BigN is ((c-1)/2)-x

x is d-1, since a=1

Anyone want to show:

RSA 2048

c=RSA 2048

d=

e=

BigN=

Remember BigN is the row in column e, where we always find (e,n,d,x,1,c)

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File: 809d349d127d59e⋯.png (14.48 KB,624x680,78:85,Factor_Tree_of_42.png)

2aeb0e No.6740 [Open thread]

The Grid is also called The End.

The Grid has cells.

Each cells has zero or infinite elements.

That a cell has infinite elements if it has any, is the first part to show.

An element represents a product, c.

c is the difference of two squares.

ab = c = dd + e = (d+n)(d+n) - (x+n)(x+n)

An element that represents a product c, the difference of two squares has a column coordinate and row coordinate.

The column coordinate is e, the remainder of taking the largest square with sides d.

The row coordinate is n, the amount added to d to make the side of the larger square in the difference of two squares. n is also the amount added to d to make it the mid point of a and b.

Each cell has coordinates (e,n)

Each cell element has coordinates (e,n,t) where t is where the element comes in the cell if ordered by size of c.

Each element c in a cell has the properties (e,n,d,x,a,b)

e is the remainder and column

n is the amount added to d to make the large square

d is the square root of c

x is the difference of a and d

a if the smaller factor of c if not equal to b

b is the larger factor of c if not equal to a

____________________________
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ac538b No.6748

See >>6694

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f89ad7 No.6591 [Open thread]

Brilliant.

Especially when I get TRIP right

____________________________
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File: f3303cc1d9385ef⋯.jpg (168.43 KB,1280x720,16:9,krach.jpg)

File: ffde81b9f8ea23e⋯.png (62.43 KB,1332x723,444:241,12-22-17.png)

File: b93dd9a8b497322⋯.gif (411.49 KB,500x452,125:113,Mario.gif)

File: 5af454ab6529d2e⋯.png (11.26 KB,500x560,25:28,image.png)

b9610b No.995 [Open thread]

Bitcoin Price Drops 22% in Four Days as Infighting Goes Public

Original — fortune.com/2017/12/21/bitcoin-price-drops-infighting/

Archive — archive.fo/FMgM3

>From a Sunday high of nearly $20,000 per digital coin, Bitcoin dropped more than 22% to a price as low as $15,262 on Thursday afternoon. Some see the drop as fallout from long-unresolved problems with Bitcoin’s infrastructure, and the increasingly intense civil war it has produced in the cryptocurrency community.

>Some recent Bitcoin buyers have described trying to actually use bitcoin for purchases, only to run into the reality of the network’s absurdly high transaction fees. Those fees have risen steadily for years due to crowding on the network.

Says the article. My take? All these currency-manipulators these people thought they could ride the coattails of, have royally fucked them over and profited billions. It's like I used to say, the Jews are gonna pump it up, then cash out all at once, killing the currency and fucking everyone over, while profiting millions and billions. It goes on to say:

>The long-running fight over how to fix the issue hit the mainstream as never before yesterday, when cryptocurrency pioneer Roger Ver appeared on CNBC. Ver was promoting Bitcoin Cash, a fork of Bitcoin created to address the digital currency’s scaling problems. Ver warned viewers that bitcoin could see “a mass exodus of people rushing for the door.” At the same time, a CNBC Twitter account was accused of “shilling” thanks to tweets that appeared to support Bitcoin Cash.

>Almost simultaneously, the cryptocurrency exchange Coinbase announced that it had halted trading in Bitcoin Cash over concerns that the exchanges’ employees may have engaged in insider trading—another possible shock to investor confidence.

>The conflicts and imperfections of the cryptocurrency world are nothing new, and neither are huge price dips—Bitcoin has seen two similarly sharp Post too long. Click here to view the full text.

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b9610b No.1528

>>1375

I also made the point that Bitcoin is worse than Fiat money. If the math gets cracked all your money becomes worth $0.

Sad.

Scam.

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8078ea No.1992

>>1528

You are correct but "If the math gets cracked" trips off the tongue so easily! Cryptography is an interesting science. It is all about doing stuff that is Really really hard one way and really really easy another way.

Crypto currencies are no more a scam than the fiat you use every day. The thing about cryptos is that they only have ONE easy way to use them. Fiat, that you know and love has tons of ways it can be cheated. Ask the FED. Ask the CFPB run by Pocahontas that literally is just a way to snag free FED money and use it to support stocks. Oh… and it is ALL DIGITAL. Just like the cryptos. Fiat is cracked as you fear constantly. All the time. They just make more as it is stolen.

Everything but hard money and paper money will go away if the stuff on this board turns out to be true. Keep that in mind. Paper money is far to small in volume to support the existing economy and far too slow. Hard money (gold/silver) is WORSE as far as distribution and use. No one has any and no one knows how to use it any more.

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b9610b No.2211

>>1992

All paper currencies will suffer because electronic transactions are RSA secured. When we find the solution it will only take me a few days to program something that uses it in an err..

practical setting. But I don't really want to do anything illegal. Maybe freak a few people out that I have their private key.

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178857 No.2323

https:/ /www.cnbc.com/2018/01/02/bitcoin-rises-after-report-says-early-facebook-investor-peter-thiel-is-buying-massive-amounts.html

Bitcoin rises after report says early Facebook investor Peter Thiel is buying massive amounts

Peter Thiel's Founders Fund has bought millions of dollars in bitcoin, The Wall Street Journal reported Tuesday, citing sources familiar with the situation.

Those holdings are worth hundreds of millions of dollars, the newspaper says. It wasn't clear whether Founders had sold any of its holdings, the report says.

Bitcoin rises more than 11 percent to trade near $14,711, according to Coinbase.

Evelyn Cheng | @chengevelyn

Published 2 Hours Ago Updated 10 Mins Ago (1/2/2018)

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a8d083 No.6215

Interesting thread popped up in qresearch bread # 1982:

>>>/qresearch/1576428

GODFATHER of ENCRYPTION: Adi Shamir

He is a co-inventor of the RSA algorithm (along with Ron Rivest and Len Adleman)

IMPORTANT: Together with Eli Biham, he discovered differential cryptanalysis, a general method for attacking block ciphers. It later emerged that differential cryptanalysis was already known — and kept a secret — by both IBM[1] and the NSA.[2]

AKA: BITCOIN/CRYPTO TRANSACTIONS NOT SECURE

Generated a good deal of discussion.

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