33b02b No.8567 [View All]
The virtual quantum computer (VQC) is a grid made of infinite yet constructable sets that follow a known pattern. Like a quantum spreadsheet.
The grid is the superposition. The collapse of that superposition will be two input parameters, d and e which can be calculated easily for all integers, c, where c is the difference of two squares. Its purpose and our goal is to learn and show the TRUTH, one of them being P=NP. Cracking RSA will be a consequence.
When the integers that are the difference of two squares are arranged into the grid and their corresponding properties are shown, a pattern emerges that shows calculation instead of searching is possible.
Glossary
Column
All cells for a given e.
Row
All cells for a given n
The grid is indexed using e, n, and t, where e is the rows, n is the columns, and t is the specific element in the cell.
Entry, record, element
one set of variables that represents one factorization for a number.
an entry = {e:n:d:x:a:b} (e, n, t)
{1:5:12:7:5:29} (1, 5, 4) is a record AKA an element AKA an entry.
ab record, nontrivial factorization, prime record
the element that contains the factorization of c that is not 1*c, hence, nontrivial.
1c record, trivial factorization
the element generated from setting a=1 and b=c
Cell
All entries for a given e,n (not to be confused with an entry itself.)
Genesis cell
e,1
Remainder Tree
The remainder tree is the result of treating d and e as c's recursively until 1 is reached, creating a tree with several to many branches.
Functions
na transform
a movement from a record in (e, n) into (e,1) where n becomes 1 and a becomes a times the n of the (e,n) record. It has also been used to refer to moving n*a records down in a cell.
T
T of number or T(input) is the triangle number function. If our input is 7, T(7) returns the 7th triangle number
T-1, inverse T
the inverse function of the triangle number function that returns the index of a given triangle number. If our input is the 7th triangle number, the function returns 7.
Variables
The map's legend is {e:n:d:x:a:b}, where c is any number that is the difference of two squares, so odd numbers are included. It is the number you want to factor. It is the number that the a and b in an entry multiply to make.
a and b are, to reiterate, the factors of c. a is the smaller factor of c, and b is the larger one.
d is the integer square root of c
e is the remainder of taking the integer square root of c. Unless c is a perfect square, a remainder will be left over.
i is the root of the large square. it is the same thing as (d+n)
j is the root of the small square. it is the same thing as (x+n). i^2 - j^2, difference of squares.
n is what you add to d to be exactly halfway between a and b, and it is the root of the large square. So it takes you from d to the large square.
x is what you add to a to make d. When added to n it makes the root of the small square.
f is what you add to c to make a square. (e is what you subtract from c to make the square below it, f adds to make the square above c.)
g is the square root of c with decimals, opposed to d, which discards decimals.
t is the third coordinate in the VQC, it is a function of x.
u is the base of a triangle that helps us calculate (x+n) for certain c values. simply put, it is a representation of (x+n). 8 times the triangle number of u plus one is x+n.
s was a variable used to demonstrate patterns in (e, 1). See "(e, 1)."
When capitalized versions of the variables are used in comparison to lowercase versions, the capitalized versions refer to the variable's value for the trivial record, and the lowercase variables refer to the values for the nontrivial record.
{e:N:d:X:A:B} (e, N, T) is the trivial element.
{e:n:d:x:a:b} (e, n, t) in this context is the nontrivial element, the prime factorization of c.
____________________________
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bd2308 No.9363
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229369 No.9365
Column (0, 1), (1, 1) and (2, 1) all have elements tied into quantum mechanics. Isn't that neat for the grid of VQC?
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4ab86f No.9366
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4ab86f No.9367
>>9363
That should read “It won’t be immediate”
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4ab86f No.9368
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bcc58e No.9369
>>9366
That's not a proper question.
Also, it is related in the most wonderous way.
It's tying in a lot of drops by VQC.
I haven't figured out how to take advantage. I see the pattern, but my lack of math is a bit of a hindrance. How to convert a c to a reasonable number?
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bcc58e No.9370
>>9360
What is the method of cloning a number, Terence?
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a4fb0c No.9371
>>9368
Everywhere but the US timezones back, although I think I saw a few websites say it ran through to the first week of July.
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Post last edited at
6987eb No.9372
>>9369
Just put it in coulomb zero lol
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4ab86f No.9373
>>9370
a=factor of d^2
b=facfor of d^2
in coulomb zero
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bd2308 No.9374
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bd2308 No.9375
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7a933a No.9376
Dead as usual with no semblance of a kept promise.
Still trust Chris?
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7a933a No.9377
You all must be so tired of being manipulated.
Do you want an end to this?
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bd2308 No.9380
>>9377
Bruh…
Brexit hasn't happened yet, silly.
But if you'd like to move things along…
By all means.
Be our guest.
But,
Be aware.
Breaking into the non-trivial is just the
Beginning.
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a3e291 No.9383
>>9376
>>9377
Oh great, another person acting like they know. Look, if you're actually paying attention to us "being manipulated" (my perspective is that it isn't the right time, but obviously we aren't told everything), then you'll know that the whole deal is people dancing around the point and not delivering. So either tell us what you have to say or don't act like you're going to.
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7a933a No.9384
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a3e291 No.9385
>>9384
Well which one are you doing?
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bd2308 No.9386
Hmmmmm…. "And theeeeen"…
Spanded Trangles…
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7a933a No.9387
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bd2308 No.9388
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7a933a No.9389
Are we already past knowing where e and f have a bearing in column zero?
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a3e291 No.9390
>>9389
You might have to be a bit more specific. What do you mean by "bearing" and are we talking about the e and f values in column 0 or the e and f values of our given c?
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a3e291 No.9391
>>9389
Also do you actually know Chris or are you involved in something we aren't aware of or what's the deal here?
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7a933a No.9392
>>9391
I've given some of the hints that this board enjoyed when they had nothing else and I want to continue in a more open manner
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a3e291 No.9393
>>9392
Well I'll have to assume it's a good idea to do this now if you're going to be vague about your position in all of this. There are a couple of us online at the moment so if you wanted to go ahead now would be a good time. By the way, when this thread fills up about 15 posts from now the next one is here >>9114
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7a933a No.9394
One of the hints that was given when the tree structure was proposed was that it required factorising d and e
A factor of d is a factor of dd, much like if a or b had factors, they would be factors of c
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7a933a No.9395
>>9390
A mathematical relationship
>>9393
It is a spiritual position
If we were to look at an element that is d * d, a + b for that element would be (d + d), or 2d, and it would exist in (0, 0, d).
If they existed we would find subsequent factorisations in (0, n) where d[t] = d
If values that were not differences of squares were encountered, we would divide by two.
The goal of looking at column zero is modus tollens. You may have heard that term before.
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bd2308 No.9396
>>9395
Caaaaaalled iiiiiiiit.
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7a933a No.9397
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7a933a No.9398
Where d^2 is between in c[t]
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7a933a No.9399
(Which is also where d is between in d[t])
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7a933a No.9400
Comparing these elements to where d is between in d[t] in row one gives the solution
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7a933a No.9401
The elements for the factorisation(s) of dd in column zero are linked to the elements d is between in column zero and row one and link to the factorisation of c via i[t]
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27f8a1 No.9402
>>9401
Shitty larps never include the fact that (0, n) and (0, N) are a false dichotomy
The solution exists as squares and square roots of elements because d is between trivial and nontrivial
Lol
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27f8a1 No.9403
>>9401
Number theory tards can’t see it because only the grid can see gaps
Pinhole vision
They need a mathematical ass whooping
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27f8a1 No.9404
Factorising d is for fags, just factorise c
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27f8a1 No.9405
Homos dont even into i[t]^2 - j[t]^2
One in coulomb nul
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a3e291 No.9406
Wait there are two of you now?
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27f8a1 No.9407
Subtracting 2 squares is the solution lol
Is was just some gay misdirection from the new scientology cult
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27f8a1 No.9408
The squares don’t exist as integers
That’s why homohobbits look at gaps
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27f8a1 No.9409
The buttstuff element in the vertical cat gym is nontrivial trivial
Has a e in one side, f in the other, homo
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a3e291 No.9410
>>9401
So you were going to go through the whole solution like you said or were you intending to just post more hints? So far everything you've said either we already know or we didn't already know but we don't know what to do with it yet.
>>9402
>>9403
>>9404
>>9405
>>9407
>>9408
>>9409
Are you going to get a little more coherent at some point? No offense, you're just kind of all over the place.
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bd2308 No.9411
>>9410
Directed towards all them links cuz i'm lazy, not AA.
And theeeeeeen?
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a3e291 No.9412
I'm going to go through my personal understanding of all these recent posts.
>>9394
>>9395
Everything in these posts is known. Every c in (0,n) is a square, so every element in any (0,n) cell with the same d will have the same c, hence the thing about subsequent factorizations. This gives us c, d, e and therefore f, but this still isn't enough to directly calculate each of the cells in (0,n) where c=cc (otherwise we could already calculate one of the cells other than cc=c*c or cc=1*cc for semiprimes etc). So this seems to be conceptual background information on another thing we're meant to do.
>>9397
Who knows what (0,e) and (0,f) are for. I had a look but I didn't see anything. Also no mention of whether we're looking at (0,-f) or (0,|f|) (although probably more importantly we just don't have anything to do with them yet to begin with). So this is another cryptic hint.
>>9398
>>9399
>>9400
>>9401
This boils down to another hint, rather than an explanation, that there's some kind of link between the elements d is between in d[t] in row one and the factor elements in (0,n) for dd, that also somehow links to one of the unknown i values (possibly the one for a[t]=na given it's explained as "i[t]"). I had a look over a couple examples and couldn't find anything.|
So as it stands right now, we've been given a couple more cryptic hints. Hopefully you were planning to come back and continue at some point. I don't know what the other person was trying to say exactly but there was definitely some familiar terminology weaved around incoherent nonsense. Also
>>9404
>just factorize c, it's so easy guys
Yeah thanks
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bd2308 No.9413
>>9412
Factoring c is easy when you're a faggot. ;)
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bd2308 No.9414
nom nom nom nom nom
bread.
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bd2308 No.9415
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a3e291 No.9416
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a3e291 No.9417
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