df0ef9 No.30327
Congratualtions! I have the feeling he will outlive Picard simply to prove he's the greatest Captain.
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5f0e09 No.30331
Will he challenge the rock?
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f831b5 No.30333
>>30331
He challenged Brianna Wu's moon rock theory.
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4ffcb9 No.30339
>>30327
He will outlive us all.
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d41d09 No.30361
Felt we should be making a bigger deal out of this.
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eadd44 No.30368
>>30361
How big you wanna go?
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71023b No.30602
>>30333 (nice)
>Brianna Wu's moon rock theory
I really don't want to know, but bile fascination and masochism compels me to ask anyway. What moon rock theory?
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1a2c87 No.30603
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a34c1b No.30611
>>30603
Moonman must terrify her.
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9601df No.30620
>>30611
John Flynt lives in constant terror of Mac Tonight.
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71023b No.30621
>>30603
Well fuck. Even a stopped clock is right twice a day.
I don't trust his math (not that he didn't just pull those numbers out of his ass) and he completely dismisses the necessary engineering (not that he has any knowledge of the subject to begin with), but what he says is basically correct. Of course, it's about like saying "fusion bombs work by mashing hydrogen together to make helium" and then attacking anybody making hydrogen on an industrial scale. The premise is factual, but the application is stupid.
Rick Robinson's First Law: An object impacting at 3 km/sec delivers kinetic energy equal to its mass in TNT. Consider the terminal velocity of a rock falling out of orbit. Then figure out how big of a rock you'd need to match the yield of a conventional nuclear weapon. Add a margin of error to compensate for ablatement during reentry. Build a mass driver on the dark side of the moon, facing roughly retrograde. Launch rocks on a return trajectory to earth. Include some form of active guidance for mid course correction and re-entry control. Drop rocks on your enemies your enemies with kinetic energy best measured in kiloton-TNT equivalents.
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6bfc85 No.30624
>>30621
Well like you I can't be assed to look up the math, but his whole "complaint" is retarded; firstly, no state has broadly recognized "ownership" of any part of the moon, so the moon (like everything else) effectively belongs to whoever has the will and capability of claiming and defending it (which is no one for the foreseeable future), so there's really no civil authority who can control what a company could do there except at where they would be launching from earth.
Secondly, any "company" with the will and capability to deploy hard military powers like shooting down satellites or releasing orbital kinetic impactors is a de-facto state actor in itself, so the idea of "legislating" what a corporation like that is "allowed" to do is nonsense (they have access to nuclear weaponry equivalents and are going to listen to what congress cucks want if they're not in agreement? Not likely).
Thirdly, big business already gets basically everything it wants out of every western government anyway (aside from small quibbles, but realistically trustbusting and laws constraining international capital and the financial sector are extremely lax, massively biased against smaller competitors and local business), so why should they care if it is the U.S. government who de jure controls the moon when they de facto decide how it would be used anyway?
Overall it's the nonsense worry of the type of guy who would cut his dick off and change his name to Brianna tbh.
Also LOL at calling guided orbital connetic impactors "dropping rocks", what a retard
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90c4dc No.30986
>>30603
socialists scared of capitalist moon rocks
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4b5353 No.31073
>>30621
>kiloton-TNT equivalents
That's the real issue here, in order to outbang a conventional nuke you'd need a fucking huge rock. The tsar bomba had a yeild of 50 megatons, that's a 50 million ton rock at 3km/s. Sure, the rock is gonna be going a lot faster than that since it's got the whole distance from the moon to accelerate, but you'd still probably need a rock with a mass of tens or even hundreds of thousands of tons, and then you've got to build something that can launch it off the moon.
It would be far, far easier just to use nukes, and you don't even need to be on the moon to do that.
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148790 No.31159
>>31073
>Far easier to use nukes
Not really. For one thing they cause radioactive fallout which really messes with your ability to occupy the cities you just bombed. An ability to precision-target military installations with large-scale destructive capabilities, that doesn't leave behind radiation is extremely valuable. There's also the whole matter that there is NOTHING THAT CAN STOP a million-ton rock hurtling in from space. A nuclear missile can be detected and shot down, and planes carrying nuclear bombs can be shot down. A giant rock? All you can do is run.
As for the logistics of launching it off the moon, don't forget that gravity is only 1/5th of Earth, and there is no atmosphere to slow it on the way. There's no need to use rockets; a simple mass-driver like a coilgun or railgun will do. So long as you can get it to L1 at around 80,000km above the Moon, even if it's crawling at that point, it'll keep falling back to Earth the rest of the way on its own.
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48326d No.32725
>>30333
His name is John Flynt
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eb365d No.32726
>>31159
the radiation isn't really a factor tbh. wear insulted clothing and face mask with air filters and you're fine.
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5839f8 No.32736
>>31159
>there is NOTHING THAT CAN STOP a million-ton rock hurtling in from space
True enough, but for the same reason it's incredibly hard to get it moving in the first place.
The change in gravitational potential energy moving an object from the surface of the Moon to L1 is something like 3MJ/kg.
Say you use a chemical gun. Combustion of H2 with O2 has an energy density of about 16MJ/kg, so ignoring questions of efficiency (e.g. heat loss), you're looking at around 200 kg fuel per ton of rock. An object dropped from the Moon has energy 15 times its mass in TNT equivalent. Together, fuel is worth roughly 75 times its mass in TNT equivalent rock delivery.
The US nuclear arsenal (in theory) could field something like 500-700 Mt of warheads. That works out to the equivalent of up to ten million tons of fuel for your gun. And you have to produce all of this on the Moon. And this ignores the materials required to actually build your guns.
A railgun has efficiencies of, say, 30% at converting electrical energy to kinetic, so that's 10MJ per kg of rock to L1, and thus 670 GJ per kiloton TNT equivalent. In other words, your yield is only 6kt per kt of energy input, and what you pay for that increase with is the massive amount of infrastructure to support many (you need to be able to launch many in a short time, after all) impossibly large guns on the desolate Moon, and the massive power supply they would need.
And launching it aside, think of what it would take simply to carve out a thousand ton rock and move it to the gun!
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