No.3796
consider a the length of AE
or a=AE.
so then:
a = AE
b = EB
c = EH
then
we know that Area□ABCD = (a+b)²,
and that Area □EFGH = c².
△AEH = ½ab, and also AEH ≡ all other triangles in between squares | proof: SSS.
so then
(a+b)²=c²+4×½ab,
a²+b²+2ab = c²+2ab,
a²+b²=c². ∎
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No.3798
Sup Δ
Haven't seen u in a while
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No.3803
Great. You've advanced to the first century (AD). What next?
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No.3826
>>3798
you are? swiss boy?
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No.3838
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No.3860
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No.3884
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