/prog/ - Programming★

>>5200 (OP)

I don't think you can do that, "1 || 2" is asking whether 1 or 2 are true.

One alternative could be to use a switch, but it isn't necessarily better.

[code]switch(x) {

case 1: case 2: case 4: case 8: case 16: break; default:

// something

break;

}[\code]

>>5201

I'm too fucking tired to fix that code block so deal with it.

Python:

if x not in [1, 2, 4, 8, 16]:

stuff

In a good language, you could have just defined some language construct to do what you wanted instead, though.

>>5216

Use a set for membership testing, ya turnip.

Easy in ruby as well:

Set[1, 2, 4, 8].include? x

And C++:

    static const std::unordered_set<int> membership = {1, 2, 4, 8};
    if (membership.count(x)) {

Really, any language with some sort of set membership check. C# has HashSet, so you could use that, though it might be slower. I'm not sure how easy C# makes static const variables, so you might incur extra overhead having to construct a set every time if not, or stick the variable into a higher scope.

>>5200 (OP)

JavaScript:

if(Math.log2(x)%1){
    //...
}